Best Answer

Assuming:

- you are rolling two six-sided dice:
- "greater than 5" does not include 5

Number of possible rolls = 36 (6x6)

28 rolls satisfy "at least one die shows a 4 or the sum of the dice is greater than 5":

(1, 4), (1, 5), (1, 6),

(2, 4), (2, 5), (2, 6),

(3, 3), (3, 4), (3, 5), (3, 6),

(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6),

(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6),

(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6),

The probability that at least on die shows a 4 or that the sum of the dice is greater than 5 is 28/36, or 7/9, or approx. 77.8%

Q: What is the probability that at least one die shows a 4 or that the sum of the dice is greater than 5?

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11 ---- 36

It is 0.8181... recurring.

The probability for dice depends on how many. For a die, it is 1/3.

With standard dice, zero.

The probability is 5/36.

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The probability, when the 2-dice total is 5, that one of the two dice shows a two is 1/2. The probability that that die is selected is 1/4.The probability, when the 2-dice total is 5, that one of the two dice shows a two is 1/2. The probability that that die is selected is 1/4.The probability, when the 2-dice total is 5, that one of the two dice shows a two is 1/2. The probability that that die is selected is 1/4.The probability, when the 2-dice total is 5, that one of the two dice shows a two is 1/2. The probability that that die is selected is 1/4.

11 ---- 36

This is the same as 1 minus the probability that neither of them are greater than three. This is 1, minus the probability of getting greater than three, squared. Rolling higher than three has a 1/2 probability, so: P(at least one greater than 3) = 1 - (1/2)2 = 1 - 1/4 = 3/4

5/36

It is 0.8181... recurring.

The probability for dice depends on how many. For a die, it is 1/3.

9/11

The probability is 1.

5/6

With standard dice, zero.

The probability of getting at least one prime number in two dice is 3/4.

The probability is 5/36.