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Q: What is the probability of rolling a number greater than or equal to eight with two dice given that a least one of the dice must show a 6?

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Assuming the numbers are 1-6, the probability is 0.

You can not roll an 8 on a 6 sided cube. The chances would be 0%, 0/0, or 0 to 0

If the cube has a 1,2,3,4,5,6,7,8, and a 9 on it, then you have 1/10 chance, or 10% because there is one that you want out of ten possibilities. If it has different digits, it would be 1/howmany digits there are, assuming that there is only one face with an eight.

Probability that it is one of these eight cards is 8/52. Hence the probability of not getting these eight cards is 44/52

There are 4 eight cards, and 12 face cards including the Jack, Queen and King.So 4 +12 =16, which is the number of eight and face cards you have in a standard deck.To find the probability, we will have 16/52 = 0.308

Related questions

The probability is 0.

Assuming that there are an equal number of even and odd faces on the eight-sided die, then the probability of rolling an even number is simply 4 in 8, or 1 in 2, or 0.5.

Assuming the numbers are 1-6, the probability is 0.

The probability of rolling a four on an eight sided octahedron is 1 in 8, or 0.125.

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It is 0.375

Assuming that the die is a regular 1 - 6 die, there is zero chance of you throwing an eight with a single six-sided die.

One roll of one normal cube: the answer is 0.

You can not roll an 8 on a 6 sided cube. The chances would be 0%, 0/0, or 0 to 0

There are 2 numbers less than 3, so the probability in this case is 2 in 8, or 1 in 4. There are 3 numbers greater than 5, so the probability in this case is 3 in 8. There are 5 numbers less than 3 or greater than 5, so the probability in this case is 5 in 8.

Each time you toss the die the probability of rolling an even number is 3 out of 6 or 1/2. So, the probability of tossing three consecutive even numbers is (1/2)3 = 1/8 = 0.125, which is one chance in eight.

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