The probability is 1/2^4 = 1/16
The conditional probability is 1/4.
It is 3/4 or 0.75
1/4 (25%)
1/4
It is 3/8.
1/16
Tossing two coins doesn't have a probability, but the events or outcomes of tossing two coins is easy to calculate. Calling the outcomes head (H)or tails (T), the set of outcomes is: HH, HT, TH and TT as follows: 2 heads = (1/2) * (1/2) = 1/4 1 head and 1 tail, can be heads on first coin tails on second, or just the opposite, there's two possible events: (1/2)*(1/2) + (1/2)*(1/2) = 1/2 2 tails = same probability as two heads = 1/4
There are 8 permutations of three coins. Of these, 3 of them have two heads, so the probability of tossing two heads on three coins is 3 in 8, or 0.375. However, you said, "at least", so that includes the case of three heads, so the probability of throwing at least two heads is 4 in 8, or 0.5. T T T T T H T H T T H H * H T T H T H * H H T * H H H *
The probability that both coins are heads is the probability of one coin landing heads multiplied by the probability of the second coin landing heads: (.5) * (.5) = .25 or (1/2) * (1/2) = 1/4
1/2 * 1/2 = 1/4 1/2= probability of landing an even number 1/2 = probability of landing a heads
By tossing two coins the possible outcomes are:H & HH & TT & HT & TThus the probability of getting exactly 1 head is 2 out 4 or 50%. If the question was what is the probability of getting at least 1 head then the probability is 3 out of 4 or 75%
Coin tosses are what we call Independent Events, meaning that the results of one toss have no effect on the next toss or any thereafter. Therefore the probability of each toss is 1/2. If, however, you want to know the probability of tossing two coins, and each coin landing heads-up, you simply multiply their probabilities together, resulting in 1/4.