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What is the probability of randomly selecting a z score greater than z equals -80?
0.7881 approx.
Fora standard normal distribution what is the probability that z is greater than 1.75?
.0401
What is the probability that z (the standard normal distribution variable) is greater than 1?
It is 0.1587
What is measured by the numerator of the z-score test statistic?
The z-score, for a value z, is the probability that a Standard Normal random variable will have a value greater than z.
What is the probability of randomly selecting a score from a normal distribution with a value greater than z equals -2?
Pr(Z > -2) = 97.725%
Given mean of 0 and deviation of 1 what is the probability that Z is greater than -1.96?
The probability of Z from minus infinity to -1.96 is 0.025. Therefore the probability of Z greater than -1.96 is 1 - 0.025 or 0.975 or 97.5%.
What is the probability of randomly selecting a z score greater than z equals -80?
0.7881 approx.
Fora standard normal distribution what is the probability that z is greater than 1.75?
.0401
What is the probability that z (the standard normal distribution variable) is greater than 1?
It is 0.1587
Using the standard normal distribution find the probability that z is greater than 1.78?
0.0375
What is measured by the numerator of the z-score test statistic?
The z-score, for a value z, is the probability that a Standard Normal random variable will have a value greater than z.
What is the probability of randomly selecting a score from a normal distribution with a value greater than z equals -2?
Pr(Z > -2) = 97.725%
What percent probability is associated with a z-value of 1.3?
None. The probability of a continuous variable taking any particular value is always zero. The probability is greater than zero only when an interval (or range) is specified.
What is the probability that z is greater than 0.75 which one is the answer 0.7734 0.72660.2734 0.2266?
0.7734 is greater than 0.75 and the rest are less than 0.75
Can a negative z score be greater than a positive z score?
Assume the z-score is relative to zero score. In simple terms, assume that we have 0 < z < z0, where z0 is the arbitrary value. Then, a negative z-score can be greater than a positive z-score (yes). How? Determine the probability of P(-2 < z < 0) and P(0 < z < 1). Then, by checking the z-value table, you should get: P(-2 < z < 0) ≈ 0.47725 P(0 < z < 1) ≈ 0.341345
If the mean is 15.2 and the standard deviation is 0.9 What is the probability that x is greater than 16.1?
z = (x-mean)/sd = (16.1-15.2)/0.9 = 0.9/0.9 = 1 Pr(Z > 1) = 15.8655 %
Suppose z has a standard normal distribution with a mean of 0 and a standard deviation of 1. the probability that z is less than 1.15 is?
probability is 43.3%
