Pr(Z > 0.5) = 0.3085 (approx).
Pr(Z > 0.5) = 0.3085 (approx).
Pr(Z > 0.5) = 0.3085 (approx).
Pr(Z > 0.5) = 0.3085 (approx).
Pr(Z > 0.5) = 0.3085 (approx).
0.7881 approx.
.0401
It is 0.1587
The z-score, for a value z, is the probability that a Standard Normal random variable will have a value greater than z.
Pr(Z > -2) = 97.725%
The probability of Z from minus infinity to -1.96 is 0.025. Therefore the probability of Z greater than -1.96 is 1 - 0.025 or 0.975 or 97.5%.
0.7881 approx.
.0401
It is 0.1587
0.0375
The z-score, for a value z, is the probability that a Standard Normal random variable will have a value greater than z.
Pr(Z > -2) = 97.725%
None. The probability of a continuous variable taking any particular value is always zero. The probability is greater than zero only when an interval (or range) is specified.
The answer is 0.2266. This can be found by looking up the z-score of 0.75 in a standard normal distribution table and subtracting that value from 1.
Assume the z-score is relative to zero score. In simple terms, assume that we have 0 < z < z0, where z0 is the arbitrary value. Then, a negative z-score can be greater than a positive z-score (yes). How? Determine the probability of P(-2 < z < 0) and P(0 < z < 1). Then, by checking the z-value table, you should get: P(-2 < z < 0) ≈ 0.47725 P(0 < z < 1) ≈ 0.341345
z = (x-mean)/sd = (16.1-15.2)/0.9 = 0.9/0.9 = 1 Pr(Z > 1) = 15.8655 %
probability is 43.3%