0.5 or 50%
The probability of a flipped coin landing heads or tails will always be 50% either way, no matter how many times you flip it.
The probability on the first flip is 50% .The probability on the 2nd flip is 50% .The probability on the 3rd flip is 50% .The probability on the 4th flip is 50% .The probability of 4 heads is (50% x 50% x 50% x 50%) = (0.5)4 = 1/16 = 6.25%
If it's an independent event then it's probability does not depend on preceding events. For example, if I flip a coin twice the probability that the coin will show 'heads' the second time is independent of what happened the first time; it's just 1/2.
The side heads is slightly heavier giving it a greater likely hood of landing on tails.
This is a probability were he is keeping the answer so he will have an equal chance of getting the same side each time
each time you flip the coin, probability to end on either side is 50% (or 0.5) (we disregard landing on the side). So, to land on the same side 7 times, it is: 0.5^7
The probability that the coin will land on heads each time is 1/2. (1/2) to the tenth power is 1/1024. This is the probability that the coin will not land on heads. Subtract it from one to get the probability that it will : 1-(1/1024)There is a 1023/1024 or about 99.90234% chance that the coin will land on heads at least once.(There is a 1/1024 chance that the coin will land on heads all four times.)
If the coin is fair, the probability is 1/4.
Each time you flip a coin, the probability of a given outcome is1/2. This is multiplied by itself every time you repeat the flip. three times: 1/2 * 1/2 * 1/2 = 1/8 decimal: .125The probability of a fair coin landing heads up is: P(H) = 1/2The probability of a fair coin landing heads up three times is: P(HHH) = (1/2)3 = 1/8= 0.125 = 12.5%One eighth or 12.5%
The probability of a fair coin landing heads up is always 0.5, regardless of previous outcomes. Each coin flip is an independent event, so the outcome of the previous flips does not affect the outcome of the next flip. Therefore, the probability of the coin landing heads up on the next flip is still 0.5.
Coin-tossing can simulate radioactive decay by assigning a probability of heads or tails to represent decay or stability of a radioactive nucleus. Consistent with the decay probability of a radioactive substance, you can randomly flip the coin to determine decay events over time. Over multiple throws, you can track the number of heads to emulate the decay rate of a radioactive substance.
This is a probability question. Probabilities are calculated with this simple equation: Chances of Success / [Chances of Success + Chances of Failure (or Total Chances)] If I flip a coin, there is one chance that it will land on heads and one chance it will land on tails. If success = landing on heads, then: Chances of Success = 1 Chances of Failure = 1 Total Chances = 2 Thus the probability that a coin will land on heads on one flip is 1/2 = .5 = 50 percent. (Note that probability can never be higher than 100 percent. If you get greater than 100 you did the problem incorrectly) Your question is unclear whether you mean the probability that a coin will land on head on any of 8 flips or all of 8 flips. To calculate either you could write out all the possible outcomes of the flips (for example: heads-heads-tails-tails-heads-tails-heads-heads) but that would take forvever. Luckily, because the outcome of one coin flip does not affect the next flip you can calculate the total probability my multiplying the probabilities of each individual outcome. For example: Probability That All 8 Flips Are Heads = Prob. Flip 1 is Heads * Prob. Flip 2 is Heads * Prob. Flip 3 is Heads...and so on Since we know that the probability of getting heads on any one flips is .5: Probability That All 8 Flips Are Heads = .5 * .5 * .5 * .5 * .5 * .5 * .5 * .5 (or .58) Probability That All 8 Flips Are Heads = .00391 or .391 percent. The probability that you will flip a heads on any of flips is similar, but instead of thinking about what is the possiblity of success, it is easier to approach it in another way. The is only one case where you will not a heads on any coin toss. That is if every outcome was tails. The probability of that occurring is the same as the probability of getting a heads on every toss because the probability of getting a heads or tails on any one toss is 50 percent. (If this does not make sense redo the problem above with tails instead of heads and see if your answer changes.) However this is the probability of FAILURE not success. This is where another probability formula comes into play: Probability of Success + Probability of Failure = 1 We know the probability of failure in this case is .00391 so: Probability of Success + .00391 = 1 Probability of Success = .9961 or 99.61 percent. Therefore, the probability of flipping a heads at least once during 8 coin flips is 99.61 percent. The probability of flipping a heads every time during 8 coin flips is .391 percent.