Each coin toss is either a head or tail. The tosses done before have no impact on the toss going on.
There are always (mathematical speaking) a 50-50 chance of head or tail.
If you had 100 tails in a row doesn't matter. It's still 50-50.
The prob. of head in 6th (or 57th or whatever) toss is 50%.
The probability of a coin landing on heads is 0.5. It does not matter which toss it is, and it does not matter what the toss history was.
the probability of getting heads-heads-heads if you toss a coin three times is 1 out of 9.
No, when you toss a coin there is a 50 percent chance it will land heads up.
1/2, or 50% since you are only asking what the probability of the last outcome is.
Each independent trial has a 1/2 probability that a heads will result. So for a sequence of 4 heads you have 1/2 x 1/2 x 1/2 x 1/2 = 1/16
the probability is actually not quite even. It would actually land heads 495 out of 1000 times because the heads side is slightly heavier
Each coin toss is either a head or tail. The tosses done before have no impact on the toss going on. There are always (mathematical speaking) a 50-50 chance of head or tail. If you had 100 tails in a row doesn't matter. It's still 50-50. The prob. of head in 6th (or 57th or whatever) toss is 50%.
there is a 1/2 chance that it will land on heads and 1/2 chance it will land on tails. it dosent matter what the stats are
Assuming each toss is independent, you can use the binomial distribution,P( X = 32) = 50C32*(p)32*(1-p)50-32 where p is the probablity of getting heads on a single toss. Assuming that the coin is fair, p = 1/2.So the answer is 50C32*(1/2)50 = 50!/(32!*18!*250 = 0.016 approx.Assuming each toss is independent, you can use the binomial distribution,P( X = 32) = 50C32*(p)32*(1-p)50-32 where p is the probablity of getting heads on a single toss. Assuming that the coin is fair, p = 1/2.So the answer is 50C32*(1/2)50 = 50!/(32!*18!*250 = 0.016 approx.Assuming each toss is independent, you can use the binomial distribution,P( X = 32) = 50C32*(p)32*(1-p)50-32 where p is the probablity of getting heads on a single toss. Assuming that the coin is fair, p = 1/2.So the answer is 50C32*(1/2)50 = 50!/(32!*18!*250 = 0.016 approx.Assuming each toss is independent, you can use the binomial distribution,P( X = 32) = 50C32*(p)32*(1-p)50-32 where p is the probablity of getting heads on a single toss. Assuming that the coin is fair, p = 1/2.So the answer is 50C32*(1/2)50 = 50!/(32!*18!*250 = 0.016 approx.
There is a 50% chance that it will land on heads each toss. You need to clarify the question: do you mean what is the probability that it will land on heads at least once, exactly once, all five times?
Most likely 5,000 times.
No, not if it is a fair coin.