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the probability of getting heads-heads-heads if you toss a coin three times is 1 out of 9.

Q: What is the probablity that the sequence will be heads-heads-heads if you toss a coin 3 times?

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the probablity of getting a head is 1/2 and 7 heads consecutively is (1/2)^7

30 maybe but i say 35 or 31

2 to 1

75

There are 8 permutations of flipping a coin 3 times, or of flipping 3 coins one time. They are, with the permutations of two heads bolded...TTTTTHTHTTHHHTTHTHHHTHHH... thus, the probability of flipping a coin 3 times and getting 2 heads is 3 in 8, or 0.375.

Related questions

the probablity of getting a head is 1/2 and 7 heads consecutively is (1/2)^7

Each independent trial has a 1/2 probability that a heads will result. So for a sequence of 4 heads you have 1/2 x 1/2 x 1/2 x 1/2 = 1/16

50%.

1 in 12 chance

50/50

The probability that a single coin flip will come up heads is 0.5.

Since there are 2 outcomes for a coin toss, and you will toss the coin 3 times the number of outcomes are 23 or 8. Since H-T-H can occur only 1 way, the probability of the H-T-H sequence is 1/8.

5 outcomes if the sequence is ignored. 24 = 16 outcomes in all.

The probability of getting five heads out of 10 tosses is the same as the probablity of getting five tales out of ten tosses. One. It will happen. When this happens, you will get zero information. In other words, this is the expected result.

The answer depends on what you are looking for: the full sequence of results, the number of heads (or tails) the number of runs, the lengths of runs, or whatever.

1 out of 555555

The answer depends on what the random variable is: it could be the number of heads, it could be the length of the longest sequence of heads (or tails), it could be the longest alternating sequence, and many other events. Since the event has not been defined, it is not possible to give a sensible answer.