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Q: What is the problem for 5R plus 6 equals 36?

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r+5r+5=-25

If: 2p+5r = q Then: p = (q-5r)/2

5s-r

13r+10=5r-46 r= r = -7

5r + r = 6r

-5r + 8r + 5 = 3r +5

9(9p + 5r)(9p + 5r)

so 26 = 4r so r = 6½

It is a linear equation in the variable r.

5r + 8 = -12Subtract 8 from each side:5r = -20Divide each side by 5:r = -4

(5r - 4)(5r + 4)

Combine the ' 9r ' and the ' -5r ' . Replace them with ' 4r '.

First, translate it into an algebraic equation:4 + 5r = -11Then we subtract 4 from both sides:4 + 5r - 4 = -11 - 4Now we can simplify our numbers together:(4 - 4) + 5r = -11 - 40 + 5r = -155r = -15Now we divide both sides by 5:(5r / 5) = (-15 / 5)r = -3

1)5r+7=13+2r+3r 2)5r+7=13+5r 3)5r's cancel 7=13 4)Subtract thirteen on both sides 7 =13 -13 -13 5)Answer is no solution because -6 doesn't equal to 0. -6=0 NO SOLUTION!!! Have fun with math!

5r = 25 is a linear equation in one variable, r. The solution is r = 5.

r=12 Work: 5r-20=40 5r=60 r=12

-7p + 5r - 6p + 3r = -7p - 6p + 5r + 3r = -(7 + 6)p + (5 + 3)r = -13p + 8r

9-4r

Simplified its 12r+3s

What you want to do is to try and get all the variables on one side by adding/subtracting. Then get the numbers on the other side and solve.

You have to combine equal terms. -5r-9s+9r+3s-6 = -5r+9r-9s+3s-6 = 4r-6s-6

3+10-r+6r = -3+9r+0 13+5r = -3+9r 16 = 4r r = 4

The question cannot be solved because, thanks to shortcomings of the browser that is used for posting questions on WA, there is no equals symbol. I suggest you resubmit using words like plus, minus, equals to get around the browser problems.

r(r + 5)

3r+10=5r-46 --> add 46 to both sides 3r+10+46=5r-46+46 3r+56=5r --> subtract 3r from both sides 3r+56-3r=5r-3r 56=2r --> divide both sides by 2 56/2=2r/2 28=r