8r + 17 = 65 8r = 65 - 17 8r = 48 r = 48 / 8 r = 6
2r + 7r - 6t - r + 7t = 8r + t
It is in its simplest form: 4r+r = 5r
5R=45
Find the possible values of r in the inequality 5 > r - 3.Answer: r < 8
-7p + 5r - 6p + 3r = -7p - 6p + 5r + 3r = -(7 + 6)p + (5 + 3)r = -13p + 8r
r+5r+5=-25
13r +10 =5r-46 13r-5r=-46-10 8r=-56 8r/8=-56/8 r=-7 use the system of letter one side and numbers one side. also when you move the numeral to the left after the equal sign you need to change the sign if it's positive make it negative, if negative make it positive.
12 + 8r - 6 = 7r - 5 - 3 8r +6 = 7r -8 r = -14
Solving for r: 16r2+18r+5=0 (2r+1)(8r+5)=0 2r+1=0 and 8r+5=0 2r=-1 .......... 8r=-5 r= -1/2 ........ r= -5/8
5r + 8 = -12Subtract 8 from each side:5r = -20Divide each side by 5:r = -4
r(r + 5)
8r + 17 = 65 8r = 48 r = 6
5*(2q + 5r)
First, translate it into an algebraic equation:4 + 5r = -11Then we subtract 4 from both sides:4 + 5r - 4 = -11 - 4Now we can simplify our numbers together:(4 - 4) + 5r = -11 - 40 + 5r = -155r = -15Now we divide both sides by 5:(5r / 5) = (-15 / 5)r = -3
5r + r = 6r
r + 11 + 8r = 29