0
Let the two consecutive integers be x and x+1. The product of these two integers is x(x+1). Setting this equal to 132 gives us the equation x(x+1) = 132. By expanding the left side of the equation, we get x^2 + x = 132. Rearranging terms, we have x^2 + x - 132 = 0. This is a quadratic equation that can be factored as (x+12)(x-11) = 0. Therefore, the two consecutive integers are 11 and 12, and their product is 132.
What else can I help you with?
Find three consecutive even integers whose sum is 132?
42, 44, 46.
Find three consecutive integers with sum 402?
Divide the sum of the three consecutive odd integers by 3: 402/3 = 134. The smallest of these integers will be two less than 134 and the largest will be two more than 134, so the three consecutive odd integers will be 132, 134, and 136.
Find three consecutive even integers whose sum is -396?
The numbers are -134, -132 and -130.
What is the answer to N x 4 - 132 equals 88?
4n - 132 = 88 + 132 +132 4n = 220 / / 4 4 n = 55
What is the answer to 22x6 equals?
22 x 6 = 132
Find the two consecutive positive integers is 132 find the integers?
The numbers are 65 and 67.
What are three consecutive integers that have the sum of 132?
43, 44, 45
What are 3 consecutive integers the have the sum of 132 and the work?
132/3 = 44 43, 44, 45
What are three consecutive even integers whose sum is 396?
3 consecutive even integers whose sum is 396 are 130, 132 and 134.
What are the two conseccutive numbers which product is 132?
11 & 12 are the integers whose product is 132.
Find three consecutive even integers whose sum is 132?
42, 44, 46.
Find three consecutive integers with sum 402?
Divide the sum of the three consecutive odd integers by 3: 402/3 = 134. The smallest of these integers will be two less than 134 and the largest will be two more than 134, so the three consecutive odd integers will be 132, 134, and 136.
Find four consecutive integers such that the sum of the second and fourth is 132?
64 65 66 67
Find three consecutive even integers whose sum is -396?
The numbers are -134, -132 and -130.
Find 2 consecutive numbers with a product of 132?
11 and 12
What three consecutive integers have a sum of 132?
X is the 1st integerX+1 would be the 2ndX+2 would be the 3rdX+(X+1)+(X+2) = 1323X+3=1323X+3-3=132-33X=129X=129/3 = 43So the consecutive integers are 43, 44, 45
Show solution of find positive integers whose product 132?
So the numbers are 11,12.
