The product of two consecutive integers is 132. Find the two integers.
They are: 11*12 = 132
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∙ 2014-03-18 12:12:1942, 44, 46.
The numbers are -134, -132 and -130.
Divide the sum of the three consecutive odd integers by 3: 402/3 = 134. The smallest of these integers will be two less than 134 and the largest will be two more than 134, so the three consecutive odd integers will be 132, 134, and 136.
4n - 132 = 88 + 132 +132 4n = 220 / / 4 4 n = 55
22 x 6 = 132
The numbers are 65 and 67.
43, 44, 45
132/3 = 44 43, 44, 45
11 & 12 are the integers whose product is 132.
3 consecutive even integers whose sum is 396 are 130, 132 and 134.
42, 44, 46.
64 65 66 67
The numbers are -134, -132 and -130.
Divide the sum of the three consecutive odd integers by 3: 402/3 = 134. The smallest of these integers will be two less than 134 and the largest will be two more than 134, so the three consecutive odd integers will be 132, 134, and 136.
11 and 12
X is the 1st integerX+1 would be the 2ndX+2 would be the 3rdX+(X+1)+(X+2) = 1323X+3=1323X+3-3=132-33X=129X=129/3 = 43So the consecutive integers are 43, 44, 45
what equals 132 is 12*11=132