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The product of two consecutive integers is 132. Find the two integers.

They are: 11*12 = 132

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Q: What is the product of two consecutive integers that equals 132?
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Related questions

Find the two consecutive positive integers is 132 find the integers?

The numbers are 65 and 67.


What are three consecutive integers that have the sum of 132?

43, 44, 45


What are 3 consecutive integers the have the sum of 132 and the work?

132/3 = 44 43, 44, 45


What are three consecutive even integers whose sum is 396?

3 consecutive even integers whose sum is 396 are 130, 132 and 134.


What are the two conseccutive numbers which product is 132?

11 & 12 are the integers whose product is 132.


Find three consecutive even integers whose sum is 132?

42, 44, 46.


Find three consecutive integers with sum 402?

Divide the sum of the three consecutive odd integers by 3: 402/3 = 134. The smallest of these integers will be two less than 134 and the largest will be two more than 134, so the three consecutive odd integers will be 132, 134, and 136.


Find four consecutive integers such that the sum of the second and fourth is 132?

64 65 66 67


Find three consecutive even integers whose sum is -396?

The numbers are -134, -132 and -130.


Find 2 consecutive numbers with a product of 132?

11 and 12


What three consecutive integers have a sum of 132?

X is the 1st integerX+1 would be the 2ndX+2 would be the 3rdX+(X+1)+(X+2) = 1323X+3=1323X+3-3=132-33X=129X=129/3 = 43So the consecutive integers are 43, 44, 45


What are two consecutive integers of 132?

The question refers to two factors of 132 that are consecutive integers. The answer is 11 & 12, as 11 x 12 = 132 This can be solved as follows. Let n be the smaller of the two numbers then (n + 1) is the other number. n(n + 1) = 132 n2 + n = 132 n2 + n - 132 = 0............which can be factored as (n + 12 )(n - 11) = 0 As we are only concerned with the positive integer result then this occurs when n - 11 = 0, that is when n = 11, thus (n + 1) = 12. NOTE : Integers can also be negative and this applies to the other solution when n + 12 = 0, so n = -12 and consequently (n + 1) = -11 giving the result that -12 x -11 = 132.