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Let the two consecutive integers be x and x+1. The product of these two integers is x(x+1). Setting this equal to 132 gives us the equation x(x+1) = 132. By expanding the left side of the equation, we get x^2 + x = 132. Rearranging terms, we have x^2 + x - 132 = 0. This is a quadratic equation that can be factored as (x+12)(x-11) = 0. Therefore, the two consecutive integers are 11 and 12, and their product is 132.

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2d ago
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10y ago

The product of two consecutive integers is 132. Find the two integers.

They are: 11*12 = 132

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Q: What is the product of two consecutive integers that equals 132?
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What are two consecutive integers of 132?

The question refers to two factors of 132 that are consecutive integers. The answer is 11 & 12, as 11 x 12 = 132 This can be solved as follows. Let n be the smaller of the two numbers then (n + 1) is the other number. n(n + 1) = 132 n2 + n = 132 n2 + n - 132 = 0............which can be factored as (n + 12 )(n - 11) = 0 As we are only concerned with the positive integer result then this occurs when n - 11 = 0, that is when n = 11, thus (n + 1) = 12. NOTE : Integers can also be negative and this applies to the other solution when n + 12 = 0, so n = -12 and consequently (n + 1) = -11 giving the result that -12 x -11 = 132.