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Let the two consecutive integers be x and x+1. The product of these two integers is x(x+1). Setting this equal to 132 gives us the equation x(x+1) = 132. By expanding the left side of the equation, we get x^2 + x = 132. Rearranging terms, we have x^2 + x - 132 = 0. This is a quadratic equation that can be factored as (x+12)(x-11) = 0. Therefore, the two consecutive integers are 11 and 12, and their product is 132.
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Find three consecutive even integers whose sum is 132?
42, 44, 46.
Find three consecutive integers with sum 402?
Divide the sum of the three consecutive odd integers by 3: 402/3 = 134. The smallest of these integers will be two less than 134 and the largest will be two more than 134, so the three consecutive odd integers will be 132, 134, and 136.
Find three consecutive even integers whose sum is -396?
The numbers are -134, -132 and -130.
What is the answer to N x 4 - 132 equals 88?
4n - 132 = 88 + 132 +132 4n = 220 / / 4 4 n = 55
What is the answer to 22x6 equals?
22 x 6 = 132
