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X^2 - 2X - 13 = 0

X = -b +/- sqrt(b^2-4ac)/2a

a = 1

b = -2

c = -13

X = -(-2) +/- sqrt[(-2)^2 - 4(1)(-13)]/2(1)

X = 2 +/- sqrt(56)/2

2 +/- [2sqrt(14)]/2

Side note: Don't forget to reduce the three twos!

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13y ago
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9y ago

Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "times", "equals", "squared".

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Q: What is the quadratic equations for x2 - 2x - 13 equals 0?
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