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The quadratic formula cannot be used to solve an equation if the coefficient of the equation x square term is what?

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0The quadratic formula cannot be used to solve an equation if the coefficient of the equation's x2-term is 0.

you use the quadratic formula in math when the quadratic equation you are solving cannot be factored.

When an equation cannot be solved for "x" to find the zeroes, the quadratic formula can be used instead for the same purpose.

Well, if the given quadratic equation cannot be factored, nor completed by the square, try using the quadratic formula.

Two.

The answer depends on the quadratic equation. And since you have not bothered to provide that crucial bit of information, I cannot provide a more useful answer.The answer depends on the quadratic equation. And since you have not bothered to provide that crucial bit of information, I cannot provide a more useful answer.The answer depends on the quadratic equation. And since you have not bothered to provide that crucial bit of information, I cannot provide a more useful answer.The answer depends on the quadratic equation. And since you have not bothered to provide that crucial bit of information, I cannot provide a more useful answer.

It is used to solve quadratic equations that cannot be factored. Usually you would factor a quadratic equation, identify the critical values and solve, but when you cannot factor you utilize the quadratic equation.

A quadratic equation is univariate: it has only one variable. A quadratic equation cannot have two variables. So, if b and c are known then it is a quadratic equation in a; if a and b are known it is a quadratic in c.Another Answer:-The question given is Pythagoras' theorem formula for a right angle triangle

When you need to find the roots of a quadratic equation and factorisation does not work (or you cannot find the factors). The quadratic equation ALWAYS works. And when appropriate, it will give the imaginary roots which, judging by this question, you may not yet be ready for.

The quadratic formula always works (as long as one considers complex numbers). "Simple rearrangement" may be quicker when the numbers look simple enough for you to decide (or rather guess) what the factors/ roots are by inspection (but the "rearrangement" method still works -- the numbers may just be more complicated). Probably the easiest quadratic is when the coefficient of x is zero (i.e. a polynomial of the form ax^2+b=0) or when there is no constant term (i.e. ax^2+bx=0) The quadratic formula cannot be used to solve an equation if a term in the equation has a degree higher than 2 (or if it can't be put in the form ax^2+bx+c=0). There are other more complex formulas for polynomials for degree 3 and 4.

Unfortunately, the browser used by Answers.com for posting questions is incapable of accepting mathematical symbols. This means that we cannot see the mathematically critical parts of the question. We are, therefore unable to determine what exactly the question is about and so cannot give a proper answer to your question. However, even allowing for that, it does not look like you have a quadratic equation and so you would not use the quadratic formula to solve it!

no only equations with x2 and lower powers can be considered quadratic. those with x3 cannot be considered quadratic, just as x2 cannot be considered linear

y=2x2 + 3x-1 To find the zeros of this equation (when y=0) set the equation = 0 0=2x2 + 3x-1 Now, you can either graph the equation in a graphing calculator and find the x intercepts (where the function crosses the x-axis and y=0) or you can factor the quadratic equation by "smiling" or reverse foiling. However, this equation cannot be easily factored. Therefore, using a graphing calculator will provide the correct answer of x= -1.780776 and x= 0.28077641 You can also use the quadratic formula where the general form of a quadratic equation is ax2 +bx+ c=0=y In order to use the quadratic formula, you simple plug the corresponding values into the x= equation. This will produce the same results as graphing and finding the x intercepts.

The satellite dish is a parabolic reflector. A parabola cannot be modeled by a linear equation because a linear equation is one that graphs as a straight line. It takes a second degree expression to plot it, and that means a quadratic equation.

CO2 is not an equation, so it cannot be balanced. It is a chemical formula.

You cannot change the subscript. You may only change the molar coefficient.

Balancing a chemical equation can often require a whole-number coefficient placed in front of a chemical formula. This upholds the Law of Conservation of Matter, which says that matter cannot be created or destroyed. These coefficients must be in the lowest possible ratio.

Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. However, assuming your question to find the roots or solutions of ax2 + bx + c = 0, the answer is x = [-b Â± sqrt(b2 - 4ac)]/2a b2 - 4ac is called the discriminant. If the discriminant > 0 then the quadratic equation has two distinct real roots. If the discriminant = 0 then the quadratic equation has one double root. If the discriminant < 0 then the quadratic equation has two distinct complex roots that are conjugates of one another.

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When balancing a chemical equation, you cannot change the subscripts in the chemical formulas, because that would be changing the identities of the substances in the equation. Each substance has its own unique chemical formula including specific subscripts for specific elements. What you can do when balancing a chemical equation, is to change the amount of a substance by adding a coefficient in front of its chemical formula.

No, it cannot be a correlation coefficient.

For a quadratic equation f(x) = ax^2 + bx + c we can use the discriminant to find out how many roots (answers) the equation has.To find this out we put it through b^2 - 4ac.If the answer is smaller than 0 (negative) then there are no real roots.If the answer is exactly 0 then there is one answer that is used twice.If the answer is bigger than 0 then the equation has two different roots.However, the discriminant cannot be used to give you the answer.e.g. f(x) = x^2 + 1x + 2 The discriminant would equal -7 so you cannot solve thatf(x) = x^2 + 4x + 4 The discriminant would equal 0 so there is a repeated root. f(-2) = 0 and again f(-2) = 0f(x) = 4x^2 + 10x + 6 The discriminant would equal 4 so there are two distinct roots. f(-3/2) = 0 and f(-1) = 0A simple way of explaining why this works is that in the quadratic equation you have (b^2 - 4ac)^(1/2) and you cannot find the square route of of a negative number.________________________________________________________________________apex = The coefficient of the x2-term can't be 0, One side of the equation must be 0,There can be no term whose degree is higher than 2.

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A stoichiometric coefficient is a whole number placed in front of a reagent's formula that indicates the molar ratio between it and another reagent in the same equation. For example, consider the chemical equation for the synthesis reaction of silver (Ag) and sulfur (S), which is:2Ag + S --> Ag2SYou see a "2" in front of silver. This indicates that you need a 2-1 ratio of silver reactant to silver sulfide product in order for the equation to balance. The goal of balancing an equation is to uphold the law of conservation of matter, which states that matter cannot be created or destroyed. If no coefficient is present, it is understood to be a 1. Using moles, the formula reads "2 moles of silver combine with 1 mole of sulfur to produce 1 mole of silver sulfide."

The equation of line can be easily made if the slope and y-intercept are known, in the form of y equals mx plus b, where m is the slope and b is the y-intercept. The quadratic equation may need to be utilized if the previous equation cannot be used.

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