Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "times", "equals". There is no equation in the question.
This can be done in an equation only. Multiply the entire equation by the LCD. This cancels every denominator leaving an equation with no fractions. EX: x/3 + 2/5 = 3/4 so the LCD for 3,5, and 4 is 60 60(x/3) + 60(2/5) = 60(3/4) 20(x) + 12(2) = 15(3) no more fractions, just solve.
3 x - 7 = -21
the equation is 2x + 4 = x - 3 solving it yields x = -7
The greatness of 4 squared and 3 squared is expressed by the equation: 16 - 9 which equals 7.3 squared equals 3 x 3 = 94 squared equals 4 x 4 = 1616 - 9 = 7
When we move numbers from one side of an equation to another we are actually performing an action to each side of the equation. For example X + 3 = 7 to get the 3 to the other side we must subtract it from the left side of the equation. What we do to one side we must also do to the other X + 3 - 3 = 7 - 3 Most people skip writing the above step and go straight to the next notation X = 7 - 3 the answer of course is X = 4
The roots of the equation are -4 and 3. Simplest solution is (x +4 )(x - 3) which multiplies out as x^2 + x - 12 = 0
3
An algebraic equation has (at least one) variable, usually called x. To solve the equation means to figure out the value of x. For example, in the equation x + 4 = 7 the solution is x = 3, because 3 + 4 = 7.
To find an equation where two numbers are solutions of x, do the following: x=-3 , x=4 x+3=0 , x-4=0 Multiply them together and set equal to zero, i.e. (x+3)(x-4) = x2-x-12 = 0
An equation where x = 4
if you are asking what x is in the equation of 12/x=4. x=3
Let x the first number, y the second number. equation 1: x/y = 4 equation 2: x+y =20 equation 3: manipulate equation 1 ----> x=4y substitute equation 3 to equation 2: 4y+y=20 5y=20 y=20/5 y=4 solve for the value of x by substituting the value of y to equations 1 or 2: using equation 1: x/4=4 x=4*4 x=16 using equation 2: x+4=20 x=20-4 x=16 Therefore, the two (2) numbers are: 4 and 16.
Do you need this equation factored or? 2x+3=x+4?
You are basically looking for an equation with an x and y value where when 4 is set as x, y would equal 7. An equation of this is: 3 + x = y when x = 4, then y = 3 + 4 = 7
2x+3=11
The equation is y = 5x - 15 or y = 5*(x - 3)
equation*6x-3*...answer*6(-4)-3=-27*...variable*x=-4*