4x2 + 6x - 3 (with no remainder)
Your quotient that you arrived at is too small. Increase the answer for the quotient, so that the remainder is from zero to (divisor minus one)
x3-x2+5x-1 with remainder 7, which the final answer would be written as:x3-x2+5x-1+[7/(4x+3)]
6x3+29x2-40x-42 divided by 6x+5 is x2+4x-10 remainder 8 or as x2+4x-10+8/(6x+5) If the answer is correct then the quotient multiplied by the divisor should be the same as the dividend:- (6x+5)*(x2+4x-10) + (6x+5)*8/(6x+5) Multiply term by term with (6x+5):- 6x3+5x2+24x2+20x-60x-50+8 Collect like terms:- 6x3+29x2-40x-42 which makes the answer correct.
390,676.238095
993
Your quotient that you arrived at is too small. Increase the answer for the quotient, so that the remainder is from zero to (divisor minus one)
Dividend: x3+4x2-9x-36 Divisor: x+3 Quotient: x2+x-12
(3x4 + 2x3 - x2 - x - 6)/(x2 + 1)= 3x2 + 2x - 4 + (-3x - 2)/(x2 + 1)= 3x2 + 2x - 4 - (3x + 2)/(x2 + 1)where the quotient is 3x2 + 2x - 4 and the remainder is -(3x + 2).
x3-x2+5x-1 with remainder 7, which the final answer would be written as:x3-x2+5x-1+[7/(4x+3)]
24
6x3+29x2-40x-42 divided by 6x+5 is x2+4x-10 remainder 8 or as x2+4x-10+8/(6x+5) If the answer is correct then the quotient multiplied by the divisor should be the same as the dividend:- (6x+5)*(x2+4x-10) + (6x+5)*8/(6x+5) Multiply term by term with (6x+5):- 6x3+5x2+24x2+20x-60x-50+8 Collect like terms:- 6x3+29x2-40x-42 which makes the answer correct.
18-(2/x)
1
390,676.238095
993
14, which is 15 minus 1.
Using the remainder theorem:- The function of x becomes f(-2) because the divisor is x+2 Substitute -2 for x in the dividend: 2x3+x-7 When: f(-2) = 2(-2)3+(-2)-7 = -25 Then: -25 is the remainder