2x^3 - 3x^2 + 4x - 3
(3x4 + 2x3 - x2 - x - 6)/(x2 + 1)= 3x2 + 2x - 4 + (-3x - 2)/(x2 + 1)= 3x2 + 2x - 4 - (3x + 2)/(x2 + 1)where the quotient is 3x2 + 2x - 4 and the remainder is -(3x + 2).
÷/÷ = +
Plus
4 divided by 9 minus 1 divided 12?
Addend plus addend equals sum Minuend minus subtrahend equals difference Multiplicand times multiplier equals product Dividend divided by divisor equals quotient
7 minus the quotient of 3 and v
The answer is -7 because 20 divided by -5 equals -4 and -11 minus -4 equals -7.
5m-t/7
18-(2/x)
4x2 + 6x - 3 (with no remainder)
36 and 9 36 divide by 9 = 4 36 minus 9 = 27
False When logs are taken, division becomes subtraction, so the log of a quotient is the log of the numerator minus the log of the denominator.
2x^3 - 3x^2 + 4x - 3
-10x = -50 Divide both sides by -10 remembering that a minus divided by a minus the quotient then becomes positive: x = 5 So: -10*5 = -50
22, because 48 divided by 2 equals 24 minus two is 22.
Dividend: x3+4x2-9x-36 Divisor: x+3 Quotient: x2+x-12