4x2 + 6x - 3 (with no remainder)
Your quotient that you arrived at is too small. Increase the answer for the quotient, so that the remainder is from zero to (divisor minus one)
x3-x2+5x-1 with remainder 7, which the final answer would be written as:x3-x2+5x-1+[7/(4x+3)]
6x3+29x2-40x-42 divided by 6x+5 is x2+4x-10 remainder 8 or as x2+4x-10+8/(6x+5) If the answer is correct then the quotient multiplied by the divisor should be the same as the dividend:- (6x+5)*(x2+4x-10) + (6x+5)*8/(6x+5) Multiply term by term with (6x+5):- 6x3+5x2+24x2+20x-60x-50+8 Collect like terms:- 6x3+29x2-40x-42 which makes the answer correct.
390,676.238095
993
Dividend: x3+4x2-9x-36 Divisor: x+3 Quotient: x2+x-12
Your quotient that you arrived at is too small. Increase the answer for the quotient, so that the remainder is from zero to (divisor minus one)
(3x4 + 2x3 - x2 - x - 6)/(x2 + 1)= 3x2 + 2x - 4 + (-3x - 2)/(x2 + 1)= 3x2 + 2x - 4 - (3x + 2)/(x2 + 1)where the quotient is 3x2 + 2x - 4 and the remainder is -(3x + 2).
x3-x2+5x-1 with remainder 7, which the final answer would be written as:x3-x2+5x-1+[7/(4x+3)]
24
6x3+29x2-40x-42 divided by 6x+5 is x2+4x-10 remainder 8 or as x2+4x-10+8/(6x+5) If the answer is correct then the quotient multiplied by the divisor should be the same as the dividend:- (6x+5)*(x2+4x-10) + (6x+5)*8/(6x+5) Multiply term by term with (6x+5):- 6x3+5x2+24x2+20x-60x-50+8 Collect like terms:- 6x3+29x2-40x-42 which makes the answer correct.
390,676.238095
18-(2/x)
1
993
14, which is 15 minus 1.
Using the remainder theorem:- The function of x becomes f(-2) because the divisor is x+2 Substitute -2 for x in the dividend: 2x3+x-7 When: f(-2) = 2(-2)3+(-2)-7 = -25 Then: -25 is the remainder