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Q: What two integers have a sum of -10 and a product of -75?

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Related questions

5 & 10

-65

-4 and -6

5 & -15

The integers 2 and 10 have a product of 20 and a sum of 12.

The answer is -10 and -8. -8 + -10= -18 -8x-10 =80.

The answer would be 10 12 and 14... 14 x 3 = 42 and 2(10 + 12) = 44. So the product of the largest integer and three is two less than twice the sum of the lower integers.

65

12 and -2

-15 and 5.

Two consecutive integers whose sum is 19 is 10 & 9; 10+9 = 19.

-10 + -8 = -18 -10 x -8 = 80 The two numbers are therefore -10 and -8.

-10 and -14

5 and 5. Range of products of two integers totalling 10 is from 9 (1 x 9) to 25. If integers must be different then 4 & 6.

-15 and 5

They are -15 and 5.

10 and 12

-11 and -10

It is not possible.

5 and 10

The integers are 9 and 10.

The integers are -11 and -10.

-6 and -4.

They are 6, 8, 10 and 12.

Add the numbers together (sum) and divide by two (average). SUM: 2 + 8 = 10 AVG: 10 / 2 = 5