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What is the range of positive and negative numbers that can be represented by a 16 bit integer?
From (-215) to (215 -1). In decimal -32768 to 32767.
What is the largest integer that can be represented using a 16 bit number?
65,535
What is the largest decimal number that a two byte integer can represent?
There are 8 bits in a byte, so a two byte integer would be 16 bits. The largest 16 bit integer possible would be 11111111111111112, which is 65535 in base 10.
Is -16 an integer or a rational number?
-16 is both a negative integer and a rational number
Is - 5 16 an integer?
No.
What is the maximum count of decimal of a 5-bit binary counter?
A 5-bit binary counter, interpreted as an unsigned integer, has a range of 0 to 31. Interpreted as a two's complement signed integer, it has a range of -16 to +15.
What is the range of integer char float for a 16 bit computer?
Consult your limits.h and math.h. For char it will be -128..127 or 0.255 (signed and unsigned).
What is the range of integer char float for a 16-bit computer?
Consult your limits.h and math.h. For char it will be -128..127 or 0.255 (signed and unsigned).
What is the Largest 16 bit positive number?
For an unsigned integer, that would be 216-1. For a signed integer in 2's complement notation, the largest number would be 215-1.
Describe the range of numbers that can be represented by a 16 bit number using two complement?
A signed 16 bit number can represent the decimal numbers -32768 to 32767.
What is the range of positive and negative numbers that can be represented by a 16 bit integer?
From (-215) to (215 -1). In decimal -32768 to 32767.
What is an unsigned integerWhat is significance of declaring a constant unsigned?
With a signed integer, the top bit is used to hold the sign of the number, so that the range of numbers that can be held is -(2number_of_bits-1) to 2number_of_bits-1 -1, whereas with an unsigned integer, all the bits are used to store the number which will always be positive and so the range is 0 to 2number_of_bits -1. For example, with 16 bits, a signed integer has the range -(215) to 215 -1 = -32768 to 32767 whereas an unsigned integer has the range 0 to 216 -1 = 0 to 65535. The point in particular to note is how the numbers (bit patterns) with the top bit set are interpreted: with unsigned ints they are greater than those without the top bit set (eg 0xffff = 65535 > 0x7fff = 32767), but with signed ints they are less (eg 0xffff = -1 < 0x7fff = 32767). I'm not sure about the significance of declaring a constant as unsigned (having never used one), but at a guess I would say it's to tell the compiler that the bit pattern is an unsigned bit pattern and to throw up a warning (or error) if it's used with a signed bit pattern, eg if used in a comparison with a signed int - ie an aid to cutting down on bugs by ensuring that things are only used for their intended purpose.
If 4 bits equals 1 nibble then what is 16 bytes called?
4bits equal 1 nibble1byte is 2 nibbles16 bytes equal ? nibbles16 x 2 = 32 nibblesIn the programming world, this actually goes beyond the nibble.4 bits = 1 nibble8 bits/2 nibbles = 1 byte16 bits/4 nibbles/2 bytes = 1 wordTypically, the 16bit word register is referred to as a signed Integer data type, and its range is -32,768 to + 32,767 (i.e. -(2^16 to (2^15)-1). Note that 1 bit is reserved for signage.From the Integer, you will often encounter:DINT - a 32 bit (i.e. 2 words) signed integerUINT - a 16 bit unsigned integerFloat/Real - a 32 bit decimal value w/ a range of +/- 1.175494e-38 to +/-3.402823e+38). Note this is not always as accurate as you one would like.String - As this is a 'conversion' of Integer to ASCII, 2 characters = 1 word
What is the difference between unsigned and int?
The value range. Example for 16-bit integers: signed: -32768..32767 unsigned: 0..65535
Explain word in 16 bit word computer?
A word in a computer is the native integer for that computer. In a 16 bit computer, a word is a 16 bit integer.
How to convert 8 bit displacement into 16 bit in relative base index addressing mode in 8086?
An 8 bit displacement is a two's complement signed value, with a possible range of -128 to +127. To convert it to an 16 bit displacement, sign extension is done. This means that the implied high byte is FFH if the high bit of the low byte is 1, or 00H if not. The resulting 16 bit displacement will still have a range of -128 to +127.
What is the largest integer that can be represented using a 16 bit number?
65,535
