0.6666 repeating
The product of two rational numbers is always a rational number.
Assuming that the number ends at that third 5, yes, the number is rational - as it has a defined end-point. If the number is equal to 3.245 recurring, then no, the number will not be rational.
Every time. The sum of two rational numbers MUST be a rational number.
There are [countably] infinite rational number between any two rational numbers. There is, therefore, no maximum.
The number 9.23 is a rational number. A rational number is any number that can be expressed as a fraction of two integers, where the denominator is not zero. In this case, 9.23 can be written as 923/100, which is a fraction of two integers, making it a rational number.
No, and I can prove it: -- The product of two rational numbers is always a rational number. -- If the two numbers happen to be the same number, then it's the square root of their product. -- Remember ... the product of two rational numbers is always a rational number. -- So the square of a rational number is always a rational number. -- So the square root of an irrational number can't be a rational number (because its square would be rational etc.).
You get a rational number.
It is always rational.
It must be a generalised rational number. Otherwise, if you select a rational number to multiply, then you will only prove it for that number.
It is a rational number.
Each of the two numbers is a rational number.
one-third 1/3