Yes, the product of two rational numbers is always a rational number.
No, and I can prove it: -- The product of two rational numbers is always a rational number. -- If the two numbers happen to be the same number, then it's the square root of their product. -- Remember ... the product of two rational numbers is always a rational number. -- So the square of a rational number is always a rational number. -- So the square root of an irrational number can't be a rational number (because its square would be rational etc.).
The product of two rational numbers is a rational number. All decimal numbers that terminate or end with a repeating sequence of digits are rational numbers. As both 0.54732814 (as written) and 0.5 are terminating decimals, they are both rational numbers. As 0.54732814 is a rational number and 0.5 is a rational number, their product will also be a rational number.
A rational number is one that can be expressed as a/b The sum of two rational numbers is: a/b + c/d =ad/bd + bc/bd =(ad+bc)/bd =e/f which is rational The difference of two rational numbers is: a/b - c/d =ab/bd - bc/bd =(ab-bc)/bd =e/f which is rational The product of two rational numbers is: (a/b)(c/d) =ac/bd =e/f which is rational
Yes, that's true.
The product of two rational numbers is always a rational number.
The product will also be a rational number
It will be rational.
Another rational number.
rational
Yes.
Yes, it is.
Yes, it is.
The product of two rational numbers is always a rational number.
No, it is always true.
The product of 2 rationals must be rational. The product of a rational and an irrational is irrational (unless the rational is 0) The product of two irrationals can be either rational or irrational.
The question is nonsense because the product of two rational numbers is never irrational.