Q: What is the value of 1 by 0?

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the value of 0 is '1'.

Its value is 1 when the statement is true and 0 otherwise.Its value is 1 when the statement is true and 0 otherwise.Its value is 1 when the statement is true and 0 otherwise.Its value is 1 when the statement is true and 0 otherwise.

1-1 = 0 so abs(1-1) = abs(0) = 0.

acording to me the value is 0 because the value of log 1 at any base is always 0.

Anything to the power of 0 is 1.

+1/0 or -1/0 or 0/0

0^1 means 0x0 which gives you zero. Do note that 1^0 and 0^1 is not the same.

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1 is an integral integer type with the numeric value 1. '1' is an integral character type with the numeric value 49. That is, ASCII character 49 returns the symbol '1'. To convert an ASCII character in the range '0' to '9' to its integral numeric value, subtract character '0' from the character. ASCII character '0' has the numeric value 48, thus '1' - '0' = 49 - 48 = 1. To convert a numeric value in the range 0 to 9 to its ASCII character equivalent, add character '0' to the value. Thus 1 + '0' = 1 + 48 = 49 = '1'.

2 x 0 x 1 + 1 = 0 + 1 = 1

The 0, in the tens' place has a value of 0. The digit 1 is in the thousandths' place - a much smaller place value but, its value is 1 times a thousandth, which is bigger than 0.

It is indeterminate as it cannot be sure if it is 0 or 1.

Use the median-of-three algorithm: int min (int a, int b) { return a<b?a:b; } int max (int a, int b) { return a<b?b:a; } int median_of_three (int a, int b, int c) { return max (min (a, b), min (max (a, b), c)); } Note that the algorithm does not cater for equal values which creates a problem when any two values are equal, because there are only two values to play with, neither of which can be regarded as being the middle value. If the equal value is the lower of the two values, the largest value is returned if and only if it is the last of the three values, otherwise the lowest value is returned. But when the equal value is the larger of the two values, the largest value is always returned. Lowest value is equal: Input: 0, 0, 1 = max (min (0, 0), min (max (0, 0), 1)) = max (0, min (0, 1)) = max (0, 1) = 1 Input: 0, 1, 0 = max (min (0, 1), min (max (0, 1), 0)) = max (0, min (1, 0)) = max (0, 0) = 0 Input: 1, 0, 0 = max (min (1, 0), min (max (1, 0), 0)) = max (0, min (1, 0)) = max (0, 0) = 0 Highest value is equal: Input: 0, 1, 1 = max (min (0, 1), min (max (0, 1), 1)) = max (0, min (1, 1)) = max (0, 1) = 1 Input: 1, 0, 1 = max (min (1, 0), min (max (1, 0), 1)) = max (0, min (1, 1)) = max (0, 1) = 1 Input: 1, 1, 0 = max (min (1, 1), min (max (1, 1), 0)) = max (1, min (1, 0)) = max (1, 0) = 1 The only way to resolve this problem and produce a consistent result is to sum all three inputs then subtract the minimum and maximum values: int median_of_three (int a, int b, int c) { return a + b + c - min (min (a, b), c) - max (max (a, b), c)); } Lowest value is equal: Input: 0, 0, 1 = 0 + 0 + 1 - min (min (0, 0), 1) - max (max (0, 0), 1) = 1 - 0 - 1 = 0 Input: 0, 1, 0 = 0 + 1 + 0 - min (min (0, 1), 0) - max (max (0, 1), 0) = 1 - 0 - 1 = 0 Input: 1, 0, 0 = 1 + 0 + 0 - min (min (1, 0), 0) - max (max (1, 0), 0) = 1 - 0 - 1 = 0 Highest value is equal: Input: 0, 1, 1 = 0 + 1 + 1 - min (min (0, 1), 1) - max (max (0, 1), 1) = 2 - 0 - 1 = 1 Input: 1, 0, 1 = 1 + 0 + 1 - min (min (1, 0), 1) - max (max (1, 0), 1) = 2 - 0 - 1 = 1 Input: 1, 1, 0 = 1 + 1 + 0 - min (min (1, 1), 0) - max (max (1, 1), 0) = 2 - 0 - 1 = 1 This makes sense because when we sort 0, 0, 1 in ascending order, 0 is in the middle, while 0, 1, 1 puts 1 in the middle.

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( 1 0 1 0 1 0 1 1 )2 = ( 171 )10

A fraction (not faction) with an absolute value of at least 1 is an improper fraction. One whose absolute value is in (0, 1) is a proper fraction.

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binarization is a process where each pixel in an image is converted into one bit and you assign the value as '1' or '0' depending upon the mean value of all the pixel.If greater then mean value then its '1' otherwise its '0'. binarization is a process where each pixel in an image is converted into one bit and you assign the value as '1' or '0' depending upon the mean value of all the pixel.If greater then mean value then its '1' otherwise its '0'. by, maneesh chandra j

-30 is the same as -(30) based on the order of operations. 30 is 1 and the opposite of it is -1. (-3)0 is taking the whole expression to the 0 power. Anything to the 0 power is 1.

True, multiplying a value less than 1 by another value less than 1 cannot increase the first value.

Because 0 doesn't have a value, obviously.

1. Anything to the power of 0 is equal to 1.

1

Binary

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