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Q: Why does the square root of 25 not have a real solution?

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the square root of 25 is 5

The square root of 25 has two solutions: SQRT(25) = + 5 and -5The square root of a number, by definition, should be positive. Hence, the square root of 25 is 5. The other square root is -5. However, strictly speaking, -5 is not the square root of 25, since it is not a positive number.* * * * *The exclusion of the negative square root is plain nonsense.

The square root of 625 is 25 because 25 x 25 = 625. 625 also has a negative root = -25.

The square root of 25 plus the square root of 36 = 11

The square root of 25 is 5, which is a rational number.

Related questions

the square root of 25 is 5

Yes. The square root of 25 is 5, which is a real number.

Because the square root of -25 would be that number that, squared, would equal -25. No number, positive or negative, can result in a negative square. Since -25 is a negative number, no number, positive or negative, can be squared to equal -25.

There is no real number [square] root of a negative number. There is a real cube root and a real fiftth root etc, but root, by itself, implies square root.

+25.

The square root of 8 over 25 is irrational, and real.

no. is not a real number

5 is the square root of 25 25 is the square root of 625 625 is the square of 25 25 is the square of 5

If by "radical" you mean "square root of", then yes. Both square roots of 25 are real numbers.

The square root of 25 is 5.

The principal root of a number is the positive real square root of the number - if it exists. Since -25 is negative, it does not have a real square root. Its square roots are the imaginary numbers +/-5i where i is the [imaginary] square root of -1. i is neither positive nor negative and so neither +5i nor -5i is a principal root.

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