If by "radical" you mean "square root of", then yes.
Both square roots of 25 are real numbers.
Sqrt(25) is -5 or +5, both of which are rational.
Sure. √6 , the square root of 6, is approximately 2.44949. It's an irrational number --you can't get it as the ratio of any two integers -- but it's real. See Can_a_real_number_be_an_irrational_number
No, it is not.
square root of 125= 25 times 5 under the radical (25 has a square root so you can take that out of the radical)= 5 times the square root of 5 (Thats your final answer with no calculator)
Yes well at least that is what is what ive learnt
It can be.
No it is not.
Yes.
Sqrt(25) is -5 or +5, both of which are rational.
The square root of 25 is +5 and -5 . Both of those numbers have several descriptions.They're both real, rational integers, and +5 is also positive and natural.
negative
Odd
Yes. The square root of 25 is 5, which is a real number.
2i radical 5 * * * * * No. it is ± i*radical(25) which is ± 5i. Not sure why the answer is requireed in radical form.
no. is not a real number
Yes, 25 is real and rational.
The radical of 350 refers to the square root of the number, which is approximately 18.71. In simplified radical form, 350 can be expressed as ( 5\sqrt{14} ), since 350 factors into ( 25 \times 14 ) and the square root of 25 is 5.