Sqrt(25) is -5 or +5, both of which are rational.
Sure. √6 , the square root of 6, is approximately 2.44949. It's an irrational number --you can't get it as the ratio of any two integers -- but it's real. See Can_a_real_number_be_an_irrational_number
No, it is not.
square root of 125= 25 times 5 under the radical (25 has a square root so you can take that out of the radical)= 5 times the square root of 5 (Thats your final answer with no calculator)
Yes well at least that is what is what ive learnt
It can be.
No it is not.
Yes.
Sqrt(25) is -5 or +5, both of which are rational.
The square root of 25 is +5 and -5 . Both of those numbers have several descriptions.They're both real, rational integers, and +5 is also positive and natural.
Odd
negative
2i radical 5 * * * * * No. it is ± i*radical(25) which is ± 5i. Not sure why the answer is requireed in radical form.
Yes. The square root of 25 is 5, which is a real number.
no. is not a real number
Yes, 25 is real and rational.
Yes, Any real number squared is a real number. In this case that number is 25.