LCM is 20 and the hcf is 10
HCF = 3... LCM = 18 !
hcf = 42, lcm = 84.
HCF is 48 and LCM is 576
HCF is 60 and the LCM is 360
hcf is 1 and LCM is 35
They are: LCM = 120 and hcf = 8
The HCF = 20 The LCM = 600
LCM = product/HCF so product = LCM/HCF in this case 380/16 which is 23.75, so the answer to your question is no.
The HCF is always a factor of the LCM of two numbers. The HCF is a factor of both the numbers which are factors of their LCM. Thus the HCF is also a factor of the LCM of the two numbers.
5 and 10 lcm- 10 and hcf= 5
hcf: 1 lcm: 112,038
The HCF helps when reducing fractions. The LCM helps when adding or subtracting fractions.
LCM = Product/HCF = 384
It's kind of an inverse relationship. The product of the GCF and LCM of two numbers is the same as the product of the original two numbers, so as the GCF increases, the LCM decreases and vice versa. LCM is divisable by HCF.
Yes: product of a & b = LCM x HCF so b = (LCM x HCF)/a
HCF - Highest Common Factor. LCM - Lowest Common Multiple.
The LCM is the product of the two numbers divided by their HCF. With 12 and 13, the HCF is 1. Therefore, the LCM will equal the product. With 12 and 14, the HCF is 2. Therefore, the LCM will be half of the product.
No. The LCM MUST be a multiple of the HCF.
hcf(5, 15) = 5 lcm(5, 15) = 15.
lcm(9, 12) = 36; hcf(9, 12) = 3.
HCF of 17 and 68 is 17 ..( Lowest Prime factor ) LCM Of 102 and 476 is 7*2^2*3*17 which is 1428 .. ==> Sum of HCF and LCM are 1428+17= 1445 .
You cannot. The numbers 2 and 12 have hcf = 2 and LCM = 12 The numbers 4 and 6 also have hcf = 2 and LCM = 12 So if you just knew the hcf and LCM you would not know which of the two was the required pair.