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Q: Can HCF and LCM of two numbers be 27 and 288?

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The LCM of two numbers is their product if and only if the two numbers are co prime, that is their HCF is 1. Otherwise their LCM in not their product, in fact, it is their product divided by their HCF.

LCM = product/HCF so product = LCM/HCF in this case 380/16 which is 23.75, so the answer to your question is no.

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The answer is 6 and 36

2 and 12

Related questions

The HCF is always a factor of the LCM of two numbers. The HCF is a factor of both the numbers which are factors of their LCM. Thus the HCF is also a factor of the LCM of the two numbers.

5 and 10 lcm- 10 and hcf= 5

Two or more numbers are needed to solve for HCF or LCM.

You cannot. The numbers 2 and 12 have hcf = 2 and LCM = 12 The numbers 4 and 6 also have hcf = 2 and LCM = 12 So if you just knew the hcf and LCM you would not know which of the two was the required pair.

The LCM of two numbers is their product if and only if the two numbers are co prime, that is their HCF is 1. Otherwise their LCM in not their product, in fact, it is their product divided by their HCF.

HCF of 17 and 68 is 17 ..( Lowest Prime factor ) LCM Of 102 and 476 is 7*2^2*3*17 which is 1428 .. ==> Sum of HCF and LCM are 1428+17= 1445 .

if the product of two numbers is 810 if there hcf is 9 find Lcm

HCF means the highest common factor of two or more numbers. LCM means the lowest common multiple of two or more numbers.

LCM = product/HCF so product = LCM/HCF in this case 380/16 which is 23.75, so the answer to your question is no.

If two numbers are expressed as ab and cb this is easier to work out. Assume that a and c have no common prime factors. Thus, the HCF of the two numbers will be b. The LCM is the two numbers multiplied by each other, divided by the HCF. So the LCM will be abc. b is a factor of abc, and so the HCF will always be a factor of their LCM.

Since the product of two numbers is equal to the product of their GCF and LCM, the GCF of two numbers is equal to their product divided by their LCM and their LCM is equal to their product divided by their GCF.

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