x3 - 6x2 + 4x + 15 = (x - 3)(x - (3/2 + √29/2))(x - (3/2 - √29/2))
⇒ roots are x = 3, x = 3/2 + √29/2 (≈ 4.19), or x = 3/2 - √29/2 (≈ -1.19)
(6 × 2) + 3 = 15
It will be: 6x2 +8x -15
x² + 8x + 15 = (x + 5)(x + 3)
(2x^2 - 5)(4x^3 + 3)
It cannot be factored because the discriminant of b2-4ac is less than zero.
5(x + 3)
4.7916427e+21
According to the rational root theorem, which of the following are possible roots of the polynomial function below?F(x) = 8x3 - 3x2 + 5x+ 15
2x3 + x2 + 15 This is a 3rd order polynomial in 'x'. It's numerical value kinda depends on the value of 'x'.
-2(2x^4 - 13x^3 + 15)
15
It is irrational