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It is 1/4 of a turn
The answer will depend on whether the rotation is clockwise or counterclockwise.
ENE plus 90 degrees (clockwise) is SSE.
Assume we want to find the ordered pair after 90° counterclockwise rotation. From (x,y), we have (-y,x). If we want to find the ordered pair after 90° clockwise rotation, then from (x,y) we have (y, -x)
The answer is A(-7, 2). To solve this problem, first convert the given points into vectors and then apply the given transformations. The vector for point T is (8, -5). After the half turn, the vector becomes (-5, -8). The vector for point W is (-2, -7). After a 90 degree clockwise rotation, the vector becomes (7, -2). The vector for point R is (6, -3). After a 90 degree counter-clockwise rotation, the vector becomes (-3, 6). Finally, the vector for point B is (-2, 7). After a 90 degree counter-clockwise rotation, the vector becomes (-7, 2). Therefore, the answer is A(-7, 2).
we swap the co-ordinates and give the new y co-ordinate the opposite sign.90 degrees clockwise(y, -x)
The answer will depend on whether the rotation is clockwise or anti-clockwise.
It is 1/4 of a turn
The answer will depend on whether the rotation is clockwise or counterclockwise.
The answer will depend on whether the rotation is clockwise or counterclockwise.
Rotation of 270 degrees clockwise or 90 degrees counter clockwise
A transformation, in the form of a rotation requires the centre of rotation to be defined. There is no centre of rotation given.
The effect of the rotation is the same as that of a 90 degree clockwise rotation. In matrix notation, it is equivalent to [post-]multiplication by the 2x2 matrix: { 0 1 } {-1 0 }
(x,y)-> (-y,x)
South. 90 degrees is 1/4 of a complete rotation, which is 360 degrees. http://www.mathsisfun.com/geometry/degrees.html
ENE plus 90 degrees (clockwise) is SSE.
Assume we want to find the ordered pair after 90° counterclockwise rotation. From (x,y), we have (-y,x). If we want to find the ordered pair after 90° clockwise rotation, then from (x,y) we have (y, -x)