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0.000 000 010 6 in scientific notation is 1.06 x 10-8 .
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Convert hexadecimal numbers A002B07D into octal numbers?
A002B07D16 -> binary A 1010 0 0000 0 0000 2 0010 B 1011 0 0000 7 0111 D 1101 A002B07D16 = 1010 0000 0000 0010 1011 0000 0111 11012 10 100 000 000 000 101 011 000 001 111 1012 -> octal 010 2 100 4 000 0 000 0 000 0 101 5 011 3 000 0 001 1 111 7 101 5 10 100 000 000 000 101 011 000 001 111 1012 = 240005301758 A002B07D16 = 24 000 530 1758
How do you write 54.01 billion in numerals?
54 010 000 000 or 5.401*1010 in standard form
How is scientific notation related to the floating point representation used by computers?
Floating point numbers are stored in scientific notation using base 2 not base 10.There are a limited number of bits so they are stored to a certain number of significant binary figures.There are various number of bytes (bits) used to store the numbers - the bits being split between the mantissa (the number) and the exponent (the power of 10 (being in the base of the storage - in binary, 10 equals 2 in decimal) by which the mantissa is multiplied to get the binary/decimal point back to where it should be), examples:Single precision (IEEE) uses 4 bytes: 8 bits for the exponent (encoding ±), 1 bit for the sign of the number and 23 bits for the number itself;Double precision (IEEE) uses 8 bytes: 11 bits for the exponent, 1 bit for the sign, 52 bits for the number;The Commodore PET used 5 bytes: 8 bits for the exponent, 1 bit for the sign and 31 bits for the number;The Sinclair QL used 6 bytes: 12 bits for the exponent (stored in 2 bytes, 16 bits, 4 bits of which were unused), 1 bit for the sign and 31 bits for the number.The numbers are stored normalised:In decimal numbers the digit before the decimal point is non-zero, ie one of {1, 2, ..., 9}.In binary numbers, the only non-zero digit is 1, so *every* floating point number in binary (except 0) has a 1 before the binary point; thus the initial 1 (before the binary point) is not stored (it is implicit).The exponent is stored by adding an offset of 2^(bits of exponent - 1), eg with 8 bit exponents it is stored by adding 2^7 = 1000 0000Zero is stored by having an exponent of zero (and mantissa of zero).Example 10 (decimal):10 (decimal) = 1010 in binary → 1.010 × 10^11 (all digits binary) which is stored in single precision as:sign = 0exponent = 1000 0000 + 0000 0011 = 1000 00011mantissa = 010 0000 0000 0000 0000 0000 (the 1 before the binary point is explicit).Example -0.75 (decimal):-0.75 decimal = -0.11 in binary (0.75 = ½ + ¼) → 1.1 × 10^-1 (all digits binary) → single precision:sign = 1exponent = 1000 0000 + (-0000 0001) = 0111 1111mantissa = 100 0000 0000 0000 0000 0000Note 0.1 in decimal is a recurring binary fraction 0.1 (decimal) = 0.0001100110011... in binary which is one reason floating point numbers have rounding issues when dealing with decimal fractions.
How much is 010 of one percent?
Since 010 = 10, 010 of 1% = 10 of 1% = 10% or 0.1
How can convert binary to octal?
To convert a binary number to an octal number, you need to know how an octal number is represented in binary. It is like this: 0 = 000 4 = 100 1 = 001 5 = 101 2 = 010 6 = 110 3 = 011 7 = 111 As you can see, an octal number consists of 3 'bits' (either a 0 of a 1). Now, to convert a binary number to an octal number, you first have to group the binary digits into groups of 3 bits (starting from the right). Then, you convert every group of bits into octal numbers. This way you get your binary number into an octal one. For example: (1010100111010010)2 We group them into groups of 3 bits, starting from the right. 1 010 100 111 010 010 As you see, we have a single digit left. We must add 0's to make it a group of 3 bits. 001 010 100 111 010 010 Then we convert every group into an octal number, according to the table above. 001 = 1 010 = 2 100 = 4 111 = 7 010 = 2 010 = 2 And in this way, you converted a binary number into an octal one. (1010100111010010)2 = (124722)8
Convert hexadecimal numbers A002B07D into octal numbers?
A002B07D16 -> binary A 1010 0 0000 0 0000 2 0010 B 1011 0 0000 7 0111 D 1101 A002B07D16 = 1010 0000 0000 0010 1011 0000 0111 11012 10 100 000 000 000 101 011 000 001 111 1012 -> octal 010 2 100 4 000 0 000 0 000 0 101 5 011 3 000 0 001 1 111 7 101 5 10 100 000 000 000 101 011 000 001 111 1012 = 240005301758 A002B07D16 = 24 000 530 1758
What number is 10 010 000 000?
10 billion 10 million.
How many years will be there in 1000000010000000 days?
1 000 000 010 000 000 days = 2.73790929 × 1012 year
How many seconds until October 16th 2008?
50, 040, 546, 092, 010, 000, 000, 000, 000
What is 13 010 in scientific notation?
13,010 = 1.301 × 104
How do you write 54.01 billion in numerals?
54 010 000 000 or 5.401*1010 in standard form
What is one hundred million and ten in figures?
100 000 010
Why can 16 bit color produce 65536 colors?
Bit is short for BInary digiT. It is binary because it can hold two values a 1 or a 0. If you had one bit colour you could get white (1) or Black (0).With 2 bits you can have 4:00 01 10 11with 3 bits you can have 8:000 001 010 011 100 101 110 111with 4 bits you can have 16:0000 ...... 1111with 16 bits you can have 65536:0000 0000 0000 0000 ........ 1111 1111 1111 1111With all the bits set to one the value is 65535 (in decimal) plus 1 for the all set to 0 (Zero) gives a total of 65536.
What number is after 9 009 999?
9, 010, 000 comes one after 9, 009, 999.
Example on how to convert octal to binary?
input: 76543210(8) output: 111 110 101 100 011 010 001 000(2)
How is scientific notation related to the floating point representation used by computers?
Floating point numbers are stored in scientific notation using base 2 not base 10.There are a limited number of bits so they are stored to a certain number of significant binary figures.There are various number of bytes (bits) used to store the numbers - the bits being split between the mantissa (the number) and the exponent (the power of 10 (being in the base of the storage - in binary, 10 equals 2 in decimal) by which the mantissa is multiplied to get the binary/decimal point back to where it should be), examples:Single precision (IEEE) uses 4 bytes: 8 bits for the exponent (encoding ±), 1 bit for the sign of the number and 23 bits for the number itself;Double precision (IEEE) uses 8 bytes: 11 bits for the exponent, 1 bit for the sign, 52 bits for the number;The Commodore PET used 5 bytes: 8 bits for the exponent, 1 bit for the sign and 31 bits for the number;The Sinclair QL used 6 bytes: 12 bits for the exponent (stored in 2 bytes, 16 bits, 4 bits of which were unused), 1 bit for the sign and 31 bits for the number.The numbers are stored normalised:In decimal numbers the digit before the decimal point is non-zero, ie one of {1, 2, ..., 9}.In binary numbers, the only non-zero digit is 1, so *every* floating point number in binary (except 0) has a 1 before the binary point; thus the initial 1 (before the binary point) is not stored (it is implicit).The exponent is stored by adding an offset of 2^(bits of exponent - 1), eg with 8 bit exponents it is stored by adding 2^7 = 1000 0000Zero is stored by having an exponent of zero (and mantissa of zero).Example 10 (decimal):10 (decimal) = 1010 in binary → 1.010 × 10^11 (all digits binary) which is stored in single precision as:sign = 0exponent = 1000 0000 + 0000 0011 = 1000 00011mantissa = 010 0000 0000 0000 0000 0000 (the 1 before the binary point is explicit).Example -0.75 (decimal):-0.75 decimal = -0.11 in binary (0.75 = ½ + ¼) → 1.1 × 10^-1 (all digits binary) → single precision:sign = 1exponent = 1000 0000 + (-0000 0001) = 0111 1111mantissa = 100 0000 0000 0000 0000 0000Note 0.1 in decimal is a recurring binary fraction 0.1 (decimal) = 0.0001100110011... in binary which is one reason floating point numbers have rounding issues when dealing with decimal fractions.
What is thicker 005 or 010?
.010 is thicker than .005
