0
We don't know until you tell us the measure of angle-A.
Wiki User
∙ 13y ago
Add your answer:
Earn +20 pts
How do you calculate the angle if you know Sin of the angle?
type the value of sine in the calculator and press 2ND SIN for sin-1, or press 2ND SIN for sin-1 and type the value of sine, because -sin(.xxxx) = angle known as inverse sine
What is the difference between sin x and sin -1 x .?
-- sin(x) is a number. It's the sine of the angle 'x'. -- sin-1(x) is an angle. It's the angle whose sine is the number 'x'.
What is the sin of a 37 degree angle?
sin(37) = 0.6018150232
What is the perimeter of a triangle when an angle of 57 degrees is opposite to a side of 14.5 inches and has another angle of 71 degrees?
The sum of tthe angles of a triangle is 180° which means the third angle is 180° - (57° + 71°) = 52° The sine rule gives: a/sin A = b/sin B = c / sin C where side a is opposites angle A, etc. The sine rule can be used to find the lengths of the other two sides when the angles are all known and one side length is known. Let angle A = 57°, then side a = 14.5 in. Let angle B = 71° and angle C = 52° Using the sine rule: a/sin A = b/ sin B → b = a × sin B/sin A Similarly, c = a × sin C/sin A → The perimeter = a + b + c = a + a × sin B/sin A + a × sin C/sin A = a(1 + sin B/sin A + sin C/sin A) = 14.5 in × (1 + sin 71° / sin 57° + sin 52° / sin 57°) ≈ 44.47 in ≈ 44.5 in
How do you construct a triangle with perimeter 150 mm and a base angle 75 degrees and 30 degrees?
Perhaps you can ask the angel to shed some divine light on the question! Suppose the base is BC, with angle B = 75 degrees angle C = 30 degrees then that angle A = 180 - (75+30) = 75 degrees. Suppose the side opposite angle A is of length a mm, the side opposite angle B is b mm and the side opposite angle C is c mm. Then by the sine rule a/sin(A) = b/(sin(B) = c/sin(C) This gives b = a*sin(B)/sin(A) and c = a*sin(C)/sin(A) Therefore, perimeter = 150 mm = a+b+c = a/sin(A) + a*sin(B)/sin(A) + a*sin(C)/sin(A) so 150 = a*{1/sin(A) + sin(B)/sin(A) + sin(C)/sin(A)} or 150 = a{x} where every term for x is known. This equation can be solved for a. So draw the base of length a. At one end, draw an angle of 75 degrees, at the other one of 30 degrees and that is it!
The refractive index of water is 1.33 a ray is incident from water on air at an angle of incidence equal to 30 degree what is the angle of refraction in air?
nwater * sin 30=nair *sin(angle of refraction) 1.33*0.5=1*sin(angle of refraction) sin(angle of refractiob)=0.665 angle of refraction inair=41.6 degrees nwater * sin 30=nair *sin(angle of refraction) 1.33*0.5=1*sin(angle of refraction) sin(angle of refractiob)=0.665 angle of refraction inair=41.6 degrees
How do you calculate the angle if you know Sin of the angle?
type the value of sine in the calculator and press 2ND SIN for sin-1, or press 2ND SIN for sin-1 and type the value of sine, because -sin(.xxxx) = angle known as inverse sine
What is the difference between sin x and sin -1 x .?
-- sin(x) is a number. It's the sine of the angle 'x'. -- sin-1(x) is an angle. It's the angle whose sine is the number 'x'.
What is the reference angle sin 285?
Sin(285) is a number, not an angle. The reference angle for 285 degrees is 285-360 = -75 degrees.
What is the sin of a 37 degree angle?
sin(37) = 0.6018150232
What is the perimeter of a triangle when an angle of 57 degrees is opposite to a side of 14.5 inches and has another angle of 71 degrees?
The sum of tthe angles of a triangle is 180° which means the third angle is 180° - (57° + 71°) = 52° The sine rule gives: a/sin A = b/sin B = c / sin C where side a is opposites angle A, etc. The sine rule can be used to find the lengths of the other two sides when the angles are all known and one side length is known. Let angle A = 57°, then side a = 14.5 in. Let angle B = 71° and angle C = 52° Using the sine rule: a/sin A = b/ sin B → b = a × sin B/sin A Similarly, c = a × sin C/sin A → The perimeter = a + b + c = a + a × sin B/sin A + a × sin C/sin A = a(1 + sin B/sin A + sin C/sin A) = 14.5 in × (1 + sin 71° / sin 57° + sin 52° / sin 57°) ≈ 44.47 in ≈ 44.5 in
If the side opposite angle A of a right triangle is 30 meters and the hypotenuse is 90 meters what is the sin of angle a?
sin of angle a = opposite/hypotenuse = 1/3 sin-1(1/3) = 19.47122063 degrees
How do you construct a triangle with perimeter 150 mm and a base angle 75 degrees and 30 degrees?
Perhaps you can ask the angel to shed some divine light on the question! Suppose the base is BC, with angle B = 75 degrees angle C = 30 degrees then that angle A = 180 - (75+30) = 75 degrees. Suppose the side opposite angle A is of length a mm, the side opposite angle B is b mm and the side opposite angle C is c mm. Then by the sine rule a/sin(A) = b/(sin(B) = c/sin(C) This gives b = a*sin(B)/sin(A) and c = a*sin(C)/sin(A) Therefore, perimeter = 150 mm = a+b+c = a/sin(A) + a*sin(B)/sin(A) + a*sin(C)/sin(A) so 150 = a*{1/sin(A) + sin(B)/sin(A) + sin(C)/sin(A)} or 150 = a{x} where every term for x is known. This equation can be solved for a. So draw the base of length a. At one end, draw an angle of 75 degrees, at the other one of 30 degrees and that is it!
How do you find sin of angle?
The sine of an angle is obtained from a right angle triangle. The other two angles are acute, or less than 90 degrees. The sin of the angle is the side opposite the angle divided by the hypotenuse.
A right angle triangle has an angle of 16.5 degrees. and a rise of 40 feet then how many feet is the hypotenuse?
sin(angle) = opposite/hypotenuse → hypotenuse = opposite/sin(angle) opposite = rise → hypotenuse = 40ft / sin 16.5° ≈ 140.84 ft
What are the basic trigonometric ratios?
Sine(Sin) Cosine(Cos) Tangent(Tan) ---- -Sin of angle A=opposite leg of angle A / hypotenuse -Cos of angle A= Adjacent leg of angle A / Hypotenuse -Tan of angle A= opposite leg of angle A / Adjacent lef of angle A
What is sine equation?
the sine rule, angle (a) and opposite length is eaqual to angle (b) and opposite length. which are also equal to angle (c) and opposite length. Sin A = Sin B = Sin C ------- -------- ---------- a -------- b -------- c
