The sign is >.
Sine is a trigonometric function.
No angle has a sine function greater than 1.
the sine of an angle can't be greater than 1.0
Sine and cosine.
Sine and cosine cannot be greater than 1 because they are the Y and X values of a point on the unit circle. Tangent, on the other hand, is sine over cosine, so its domain is (-infinity,+infinity), with an asymptote occurring every odd pi/2.
no - nor less than minus 1.
It's not. The sine of 32 degrees is approximately 0.53. The sine of 59 degrees is approximately 0.86. For a definition of sine, see: http://en.wikipedia.org/wiki/Trigonometric_function .
No, the co-secant (csc) of an angle cannot be less than 1 or greater than -1. This is because the co-secant is defined as the reciprocal of the sine function (csc(θ) = 1/sin(θ)). Since the sine of an angle ranges from -1 to 1, the co-secant will either be greater than or equal to 1 when sine is positive or less than or equal to -1 when sine is negative.
No. The sine of an acute angle is less than 1. An acute angle is less than 90 degrees. The sine of 0 degrees is 0, and the sine of 90 degrees is +1. So the sines of the angles between 0 degrees and 90 degrees are less than 1.
If you look at the definition of the sine function in a triangle, you'll discover that the maximum possible value of the sine function is ' 1 ' and the minimum possible value is ' -1 '. There's no angle that can have a sine greater than ' 1 ' or less than ' -1 '. So the absolute value of the sine of anything is always ' 1 ' or less.
lol! it can be less than 1 too, upto -1! it cannot be greater than 1 because hypotenuse is always longer than the adjacent and opposite side... (from pythagoras theorem)
The sine of an angle x is defined as the ratio of the opposing side to the hypotenuse, in a right triangle having x as one of its acute angles. If it was greater than 1, it would mean the opposing side was longer than the hypotenuse. Try to draw a right triangle with one of the sides longer than the diagonal. You'll notice it's impossible. So the sine cannot be greater than 1. Fitting the triangle into a circle of radius 1, such that the angle x is located at the origin and the hypotenuse is a radius of the circle, you can define "sine of x" for any angle. Since the triangle may end up flipped in any direction, including the negative x and y axis, it turns out that the sine of any number is between -1 and +1. The cosine is simply the sine of the complementary angle (90 - x). So it must also be contained between -1 and +1.
You can only find the inverse of sine for number less than or greater than 1. An improper fraction is not acceptable either because the ratio is opposite over hypotenuse. The hypotenuse will always be the longest, so there you go.