No. The sine of an acute angle is less than 1. An acute angle is less than 90 degrees. The sine of 0 degrees is 0, and the sine of 90 degrees is +1. So the sines of the angles between 0 degrees and 90 degrees are less than 1.
An acute angle has less than 90 degrees, an obtuse angle has greater than 90 degree but less than 180 degrees. A reflex angle has greater than 180 degrees.When in doubt, google image search.
The sine and cosine of acute angles are equal only for 45° sin45° = cos 45° = 1/sqrt(2) = 0.7071
It is an obtuse triangle having 1 obtuse angle and 2 different acute angles Or it is an isosceles triangle having 1 obtuse angle and 2 equal acute angles
There are 4 components of angles and they are:- 1 Acute angle which is greater than 0 but less than 90 degrees 2 Right angle which is 90 degrees 3 Obtuse angle which is greater than 90 but less than 180 degrees 4 Reflex angle which is greater than 180 but less than 360 degrees
home improvement
No angle has a sine function greater than 1.
Well, the easiest way to go at it is simply to remember thatthe sine and cosine of any angle are always less than 1 .
no - nor less than minus 1.
No, the co-secant (csc) of an angle cannot be less than 1 or greater than -1. This is because the co-secant is defined as the reciprocal of the sine function (csc(θ) = 1/sin(θ)). Since the sine of an angle ranges from -1 to 1, the co-secant will either be greater than or equal to 1 when sine is positive or less than or equal to -1 when sine is negative.
You can only find the inverse of sine for number less than or greater than 1. An improper fraction is not acceptable either because the ratio is opposite over hypotenuse. The hypotenuse will always be the longest, so there you go.
1 acute angle = 1 acute angle
The sine of an angle x is defined as the ratio of the opposing side to the hypotenuse, in a right triangle having x as one of its acute angles. If it was greater than 1, it would mean the opposing side was longer than the hypotenuse. Try to draw a right triangle with one of the sides longer than the diagonal. You'll notice it's impossible. So the sine cannot be greater than 1. Fitting the triangle into a circle of radius 1, such that the angle x is located at the origin and the hypotenuse is a radius of the circle, you can define "sine of x" for any angle. Since the triangle may end up flipped in any direction, including the negative x and y axis, it turns out that the sine of any number is between -1 and +1. The cosine is simply the sine of the complementary angle (90 - x). So it must also be contained between -1 and +1.
An acute angle has less than 90 degrees, an obtuse angle has greater than 90 degree but less than 180 degrees. A reflex angle has greater than 180 degrees.When in doubt, google image search.
To find the acute angle of the ramp, you can use the sine function in trigonometry. The sine of the angle ( \theta ) is equal to the opposite side (height) divided by the hypotenuse (ramp length): ( \sin(\theta) = \frac{0.643}{1} ). Calculating this gives ( \theta = \arcsin(0.643) ), which is approximately 40.0 degrees. Thus, the acute angle of the ramp is about 40 degrees.
It is 1.
an acute angle
An acute angle because it's greater than 0 but less than 90 degrees