360/8 = 45 degrees
Assuming you mean "what is the size of the exterior angle of a regular octagon", then: The sum of the exterior angles of any polygon is 360o. Thus for a regular octagon, each is 360o ÷ 8 = 45o.
The measure of the exterior angle of a convex octagon is indeterminate.
The exterior angles of any polygon add up to 360. 360/8 = 45
The exterior angles of any polygon add up to 360. 360/8 = 45
45 degrees.
135 degrees and its exterior angle is 45 degrees
180 minus interior angle = exterior angle
Providing that it is a regular octagon each exterior angle measures 45 degrees.
The hexagon has the larger exterior angle.
Assuming you mean "what is the size of the exterior angle of a regular octagon", then: The sum of the exterior angles of any polygon is 360o. Thus for a regular octagon, each is 360o ÷ 8 = 45o.
The measure of the exterior angle of a convex octagon is indeterminate.
The exterior angle of a general octagon is any angle less than 180 degrees. The sum of the exterior angles of a polygon is 360 degrees. If the octagon is regular, then each of its 8 exterior angles is equal to 360/8 = 45 degrees.
Each exterior angle of a regular octagon: 360/8 = 45 degrees
The exterior angles of any polygon add up to 360. 360/8 = 45
The external angle of a regular octagon is 225 degrees. Each internal angle of a regular octagon is 135 degrees.
The exterior angles of any polygon add up to 360. 360/8 = 45
Providing that it is a regular octagon: Exterior angle: 45 degrees Interior angle: 135 degrees