360/8 = 45 degrees
Assuming you mean "what is the size of the exterior angle of a regular octagon", then: The sum of the exterior angles of any polygon is 360o. Thus for a regular octagon, each is 360o ÷ 8 = 45o.
The measure of the exterior angle of a convex octagon is indeterminate.
The exterior angles of any polygon add up to 360. 360/8 = 45
The exterior angles of any polygon add up to 360. 360/8 = 45
45 degrees.
180 minus interior angle = exterior angle
135 degrees and its exterior angle is 45 degrees
In an octagon, the sum of all exterior angles is always 360 degrees. Therefore, each exterior angle of an octagon measures 360 degrees divided by 8, which equals 45 degrees. This means that each exterior angle of an octagon is 45 degrees.
Providing that it is a regular octagon each exterior angle measures 45 degrees.
The hexagon has the larger exterior angle.
Assuming you mean "what is the size of the exterior angle of a regular octagon", then: The sum of the exterior angles of any polygon is 360o. Thus for a regular octagon, each is 360o ÷ 8 = 45o.
The measure of the exterior angle of a convex octagon is indeterminate.
The exterior angle of a general octagon is any angle less than 180 degrees. The sum of the exterior angles of a polygon is 360 degrees. If the octagon is regular, then each of its 8 exterior angles is equal to 360/8 = 45 degrees.
Each exterior angle of a regular octagon: 360/8 = 45 degrees
The exterior angles of any polygon add up to 360. 360/8 = 45
The exterior angles of any polygon add up to 360. 360/8 = 45
Providing that it is a regular octagon: Exterior angle: 45 degrees Interior angle: 135 degrees