Need point slope form. Y = mX + c
4X + 2Y = 10
2Y = - 4X + 10
Y = - 2X + 5
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slope(m) = - 2
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10 is.
If: y = 2/5x+10 then the perpendicular slope is -5/2x or -2.5x
2x+y = 10 or y = -2x + 10 so the slope is -2
The equation in point slope of the line which passes through -2 -3 and is parallel to 3x plus 2y 10 is y=-1.5x.
Answer:-10/2=-5Solution:The relation between the line slope and it's perpendicular line slope is negative reciprocal, i.e.Slope of the line perpendicular = -1/Slope of the line= -1/(2/10)= -1 x 10/2= -10/2= -5
It is a straight line equation which can be rearranged to y = 3x+10 in slope intercept form
It has infinite slope.
The slope is 3.
The slope is 3.(y = mx + b, m is the slope: y=3x+10)
2x - 5y = -10 So 5y = 2x + 10 and therefore y = (2/5)*x plus something So the slope is 2/5 or 0.4
The Slope of the line 4x + 2y = 10 is -2. The Y-intercept is 5. To figure out how to do this problem convert the equation in the form of y = mx + c Here m is the slope and c is the y intercept. For above example, y = (-2)x +5. Therefore, slope is -2.
Points: (10, 8) and (15, 8) Slope: 0 It will be a straight horizontal line