A straight line, passing through the point (0,5) with a gradient of -3.
It is a straight line equation which can be rearranged to y = 3x+10 in slope intercept form
y=3x+4 -3x+y=4 x=-1/3
3x + x + 10 + x = 5x + 10
The gradient (slope) of 3y = 4x+5 is 4/33y = 4x+5y = 4/3x+5/3y=mx+c(m = gradient)mx+c = 4/3x+5/3m = 4/3
3/1
The gradient of the given line is 2/3. Gradient of the perpendicular is -3/2 The equation, therefore, is y = -(3/2)x + 5 or 2y = -3x + 10 or 3x + 2y - 10 = 0
y=2 + 3x seems like a linear equation, therefore, y=3x + 2.The gradient is 3.
Assuming the equation of the given line is y = 3x + 4, its gradient is 3.Therefore the gradient of the required line is 3. The line passes through (3, 1) and so its equation is y - 1 = 3*(x - 3) = 3x - 9 So y = 3x - 8
A straight line, passing through the point (0,5) with a gradient of -3.
y=3x+2 so the gradient or slope is 3
An equation such as y = mx + c is said to be in standard form. From such an equation, Gradient = coefficient of x = 3
y=3x
It is a straight line equation which can be rearranged to y = 3x+10 in slope intercept form
y=3x+4 -3x+y=4 x=-1/3
1
It would be a straight line with gradient 3, which would intercept the y axis at the point (0,2).