A line perpendicular to the x-axis does not have a slope nor a y-intercept and so it is not possible to answer the question.
An intercept is where the graph crosses an axis.A line in slope-intercept form is in the form y = ax + b, where "a" is the slope, and "b" is the y-intercept. For example, if y = 3x -4, the slope of the line is 3, and it crosses the y-axis at -4.
y = mx + b Where m is the slope and b is the intercept on the y-axis.
b is where the line on the graph intercepts the y axis ( The vertical Line ) in a slope intercept equation
y=mx+b
The equation of a line that is perpendicular to 3y = -x + 9 and that has a y intercept of 6 is y = 3x + 6. The slope of the first line is -1/3, from the slope-intercept form y = mx + b, or y = -x/3 + 3. The perpendicular slope is 3, by negating and inverting -1/3. Add the intercept to the slope-intercept form and you get y = 3x + 6.
It is: y = mx+b whereas m is the slope and b is the y intercept
Get the slope of the given line, by putting it into slope-intercept form. Then you can divide minus one by this slope, to get the slope of any perpendicular line.
y=mx+b where m is the slope and b is the y-intercept (place on the y-axis where the line crosses).
It cuts through the x axis and it is an extension of the line cutting through the y axis which is the y intercept
A line perpendicular to the y-axis is a horizontal line (slope = 0) and is of the form y = b Therefore the required line is y = 5
It is part of the equation that intercepts the y axis For example the straight line equation: y = 2x+4 is in slope-intercept form and 4 is the y intercept and 2 is the slope.
y = mx + bthe m is the slope in slope-intercept form and the b is the y-intercept (where the line touches the y-axis)