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Without an equality sign and not knowing some of the plus or minus values of the given terms it can't be considered to be a straight line equation.

But if you mean: y = 12x-3 a given point of (5, 0)

Then the perpendicular equation is: y = -1/12x+5/12 whereas -1/12 is the slope and 5/12 is the y intercept

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Q: What is the slope intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation. (50) y 12 (-3)?
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