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As for example the perpendicular equation to line y = 2x+6 could be y = -1/2x+6 because the negative reciprocal of 2x is -1/2x

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Q: How do I write an equation in slope-intercept form for a line perpendicular to the graph of the equation that passes through the x-intercept of that line?
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What is the equation of the line that it is perpendicular to y7x-3 and passes through the origin?

If you mean 7 = 7x-3 then the perpendicular slope is -1/7 and the equation is y = -1/7x


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Known equation: 5x -2y = 3 or y = 5/2x -3/2 Slope of equation: 5/2 Slope of perpendicular equation: -2/5 Perpendicular equation: y --4 = -2/5(x -3) => 5y = -2x -14 Perpendicular equation in its general form: 2x+5y+14 = 0


What is the equation of a line that passes through 3 -4 and is perpendicular to 5x -2y equals 3 on the Cartesian plane?

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