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-3x + 2y = 8To get into slope intercept, we must set the equation equal to y2y = 3x + 8y = 3/2x + 8/2y = 3/2x + 4
2x-6y = 20 -6y = -2x+20 y = 1/3x-20/6 The slope is 1/3
y=2/3x+4
If you mean: 2x-3y = 8 then y = 2/3x-8/3 and the perpendicular slope is -3/2
Convert the equation into y = mx + b form: 2x + 3y = 6 -2x -2x 3y = 6 - 2x Divide both sides by 3: y = 2- 2/3x If we move the terms around to put in in y = mx + b: y = -2/3x + 2 m is the slope, so the slope is -2/3
-2
If you mean: -2x-3y = 24 then-3y = 2x + 24 => y = (2x+24)/(-3) => y = -2/3x-8where -2/3 is the slope and -8 is the y-intercept
2x-3y = 4 -3y = -2x+4 y = 2/3x-4/3 So the slope is 2/3 and the intercept is -4/3
2X + 3Y = 24 subtract 2X from both sides 3Y = - 2X + 24 divide both sides by 3 Y = - 2/3X + 8 slope(m) = - 2/3
I am assuming you mean the form Y=MX+C 2x-3y-6=0 2x-6=3y 2/3x-2=y y=2/3x-2 slope =2/3
2x-3y=16 Write this in standard form (y = mx+c), 3y = 2x-16 or y = 2/3x - 16/3 so the slope is 2/3
2x + 3y = 5 So 3y = -2x + 5 or y = -2/3x + 5 Now that the equation is in standard form, you just read the slope off as the coefficient of x, ie slope = -2/3