2x-3y=16 Write this in standard form (y = mx+c), 3y = 2x-16 or y = 2/3x - 16/3 so the slope is 2/3
The slope would be 3/4
1.6x - 3.2y = 16 3.2y = 1.6x - 16 y = 0.5x - 5 So slope = coefficient of x = 0.5
The slope-intercept form of the equation of a line is y = mx + b, where m is the slope and b is the y-intercept. To put 3x - 2y = 16 in slope-intercept form just requires a little rearranging: 3x - 2y = 16 -2y = -3x + 16 (subtract 3x from both sides) y = 3/2x - 8 (divide all terms by -2) Now the equation is in slope-intercept form. The slope m is 3/2; the y-intercept is -8.
The slope is normally represented by m so it is 0.
The slope is -4
Put the equation in this form: y=mx+b. Then m will be the slope. 2x3y+6=0 2x3y=-6 3y=-6/2x y=-2/2x y=-1/x This equation does not describe a straight line, but rather, it describes a curve.
the slope of the line is -4
Slope of a line perpendicular to x-y=16
If: 3x+y = 16 Then: y = -3x+16 whereas -3 is the slope and 16 is the y intercept
16
16
If 8x + 4y = 16, then y = - 2x + 4 Thus the slope is -2 and the intercept is 4.
The slope would be 3/4
To function form. - 7X - 4Y = 16 - 4Y = 7X + 16 Y = - 7/4X - 4 ------------------------ The slope is, - 7/4 --------
3X - 2Y = - 16 - 2Y = - 3X - 16 Y = (3/2)X + 8 ==============slope intercept form
3x - 4y -16 = 0 Algebraically rearrange to to make '4y' the subject. Hence 4y = 3x - 16 ( Note the change of sign, on taking the '4y' across the equals to replace the zero. ). Divide both sides by ;4; y = (3/4)x - 16/4 y = ( 3/4)x - 4 Hence the slope is ' 3/4 ' and the y-intersect is '-4'. NB For all straight line of the form y = mx + c 'm' is the slope , and 'c' is the y-intersect. All you need to do on being given linear equations of the form px + ny + c = o or px + c = ny or px + ny = c etc. is to algebraically rearrange into the form of y = mx + c , making sure you change the signs correctly, and then dividing both sides by the coefficient of 'y' .
1.6x - 3.2y = 16 3.2y = 1.6x - 16 y = 0.5x - 5 So slope = coefficient of x = 0.5