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2x-3y=16 Write this in standard form (y = mx+c), 3y = 2x-16 or y = 2/3x - 16/3 so the slope is 2/3

Q: Slope of 2x-3y equals 16

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The slope would be 3/4

1.6x - 3.2y = 16 3.2y = 1.6x - 16 y = 0.5x - 5 So slope = coefficient of x = 0.5

The slope is normally represented by m so it is 0.

The slope-intercept form of the equation of a line is y = mx + b, where m is the slope and b is the y-intercept. To put 3x - 2y = 16 in slope-intercept form just requires a little rearranging: 3x - 2y = 16 -2y = -3x + 16 (subtract 3x from both sides) y = 3/2x - 8 (divide all terms by -2) Now the equation is in slope-intercept form. The slope m is 3/2; the y-intercept is -8.

The slope is -4

Related questions

Put the equation in this form: y=mx+b. Then m will be the slope. 2x3y+6=0 2x3y=-6 3y=-6/2x y=-2/2x y=-1/x This equation does not describe a straight line, but rather, it describes a curve.

the slope of the line is -4

Slope of a line perpendicular to x-y=16

If: 3x+y = 16 Then: y = -3x+16 whereas -3 is the slope and 16 is the y intercept

16

16

-4 is the slope because -2y=8x+16 y= -4x - 8

If 8x + 4y = 16, then y = - 2x + 4 Thus the slope is -2 and the intercept is 4.

The slope would be 3/4

To function form. - 7X - 4Y = 16 - 4Y = 7X + 16 Y = - 7/4X - 4 ------------------------ The slope is, - 7/4 --------

3X - 2Y = - 16 - 2Y = - 3X - 16 Y = (3/2)X + 8 ==============slope intercept form

If: 3x-4y-16 = 0 Then: -4y = -3x+16 And: y = 0.75x-4 which is now in slope-intercept form So the slope is 3/4 or 0.75