Slope of a line = m
slope of perpendicular line = -1/m
Slope: (2-4)/(0--3) = -2/3 Perpendicular slope: 3/2
Points: (5, -1) and (2, -5) Slope: 4/3 Perpendicular slope: -3/4
If you mean: 2x-3y = 8 then y = 2/3x-8/3 and the perpendicular slope is -3/2
x-3y = 9 -3y = -x+9 y = 1/3x -3 Perpendicular slope = -3
Endpoints: (-1, 3) and (-2, -5) Midpoint: (-3/2, -1) Slope: 8 Perpendicular slope: -1/8 Perpendicular bisector equation: y --1 = -1/8--3/2 => y = -1/8x -19/16
Perpendicular lines have slopes whose product is -1. As this is always true, if we think of .33 as about 1/3, then the perpendicular line would have a slope of -1/(1/3) which is -3.
x - 4y = 3 is the slope of a line perpendicular to line whose equation is y -5 3x plus 8 3.
4y= -3x + 12 y = -3/4x + 3 The perpendicular slope is 4/3
To find the slope of a perpendicular line, take the negative reciprocal of the slope of the given line. (Flip the top and bottom of the fraction and change the sign.) The slope of 3 can be written as 3/1. The slope of a line that is perpendicular is -1/3.
3x+y = 4 y = -3x+4 Perpendicular slope: 1/3
Without an equality sign it can't be considered to be an equation but in general if the slope was 3 then the perpendicular would be -1/3
The slope of two lines are perpendicular only if their slopes multiplied together equal -1 (m1*m2 = -1). So if a line has a slope of -3 then a line perpendicular to this one has a slope of -1/-3 or 1/3.
-5/3
- 1/3
-5/3 it is always the opposite reciprocal for a perpendicular slope
Slope of the given line is 3/7 So slope of perpendicular line is -7/3
Slope of given line = -3 Therefore, slope of perpendicular = 1/3