Do you mean y = -8x+20
Then if so the perpendicular slope is positive 1/8.
y=-x-4as this is in the form of y=mx+b, the slope of this line is -1.5x + 5y = 20x + y = 4y = -x + 4the slope of this line is -1.Since the slope of each of the two lines are the same (-1) they are in fact parallel to each other, not perpendicular.
The slope is -1. (30, 10) and (20, 20) are both (x, y) coordinates, and can both be plotted on a 2-D graph. For every point that you go forward, you also have to go 1 point down to meet both points.
Perpendicular slope: -2/5 Perpendicular equation: y--4 = -2/5(x-3) => 5y--20 = -2x-3 => 5y = -2x-14 Perpendicular equation in its general form: 2x+5y+14 = 0
32.6
5x - 10 = -20This equation can be restated as 5x = -10 : x = -2This is the equation of a straight line perpendicular to the x axis and passing through the point x = -2. There is no y intercept and the slope is indeterminate.
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Points: (-18, -7) and (-20-9) Slope works out as 1
y=-x-4as this is in the form of y=mx+b, the slope of this line is -1.5x + 5y = 20x + y = 4y = -x + 4the slope of this line is -1.Since the slope of each of the two lines are the same (-1) they are in fact parallel to each other, not perpendicular.
The slope is -1. (30, 10) and (20, 20) are both (x, y) coordinates, and can both be plotted on a 2-D graph. For every point that you go forward, you also have to go 1 point down to meet both points.
Known equation: 5x -2y=3 => y=5/2x -1.5 Slope of equation: 5/2 Perpendicular slope: -2/5 Perpendicular equation: y--4=-2/5(x-3) => 5y--20=-2x+6 => 5y=-2x-14 Therefore the perpendicular in its general form is: 2x+5y+14 = 0
Perpendicular slope: -2/5 Perpendicular equation: y--4 = -2/5(x-3) => 5y--20 = -2x-3 => 5y = -2x-14 Perpendicular equation in its general form: 2x+5y+14 = 0
Points: (14, 5) and (20, 4) Slope: -1/6
The slope or gradient of a line that represented the change in savings over time would increase (in this case it would double). This is because in the example in your question, you would be saving twice as much money per unit time. As such the gradient of the line would change from 20 (20 / 1) to 40 (40 / 1).
Parallel lines have the same slope. So if you have y=x+20 for example, the slope is 1 and any parallel line has slope 1 also. I think your equation is x=y+20 but since the+ and - don't show up i am not sure If it is we can rewrite it as -y=-x+20 or y=x-20 and slope is still 1 so any parallel line has slope 1.
It is 2√5 ≈ 4.47 units.To solve this:Find the equation of the line perpendicular to y = 2x + 10 that passes through the point (2, 4);Find the point where this line meets y = 2x + 10Find the distance from this point to (2, 4) using PythagorasThe slope of the perpendicular line (m') to a line with slope m is such that mm' = -1, ie m' = -1/mFor y = 2x + 10, the perpendicular line has slope -1/2, and so the line that passes through (2, 4) with this slope is given by:y - 4 = -½(x - 2)→ 2y - 8 = -x + 2→ 2y + x = 10To find where this meets the line y = 2x + 10, substitute for y in the equation of the perpendicular line and solve for x:y = 2x + 102y + x = 10→ 2(2x + 10) + x = 10→ 4x + 20 + x = 10→ 5x = -10→ x = -2Now use one of the equations to solve for y:y = 2x + 10→ y = 2(-2) + 10→ y = -4 + 10 = 6This the perpendicular line from (2, 4) meets the line y = 2x + 10 at the point (-2, 6)The distance between these two points is given by:distance = √((-2 - 2)² + (6 - 4)²) = √(16 + 4) = √20 = 2√5 ≈ 4.47 units
I believe the slope would be: -4 / 3
32.6