x - 4y = 3 is the slope of a line perpendicular to line whose equation is y -5 3x plus 8 3.
the slope will be positive 1.5x the whole equation is y=4.5+1.5x
1.67 or 1.667
It is -1/2
Without an equality sign the given terms can't be considered to be a straight line equation.
For the line 2x + y = 8 , the slope equals ( -2 ) so the required slope of the line which is perpendicular to it is equal to (+1/2 )
what is the slope of the line that has the equation 4x+2y=12?
Without an equality sign it can't be considered to be an equation but in general if the slope was 3 then the perpendicular would be -1/3
3x+y = 4 y = -3x+4 Perpendicular slope: 1/3
ax + by = cThe graph if that equation is a straight line whose slope is (-a/b)and whose y-intercept is (c/b).
4y= -3x + 12 y = -3/4x + 3 The perpendicular slope is 4/3