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Q: What is the smallest digit that can be placed in the blank so that 67 and 45 is divisible by 3?

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0.

smallest 4-digit number divisible by 2 = 1000

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2. To test a number to be divisible by 3, add up the digits and if the sum is divisible by 3, so is the original number. If not, the excess over a multiple of 3 gives the remainder when the original number is divided by 3. Subtract this remainder from 3 and this gives the smallest digit to replace the blank; unless the remainder is 0, in which case the blank can be replaced by a 0: 8 + 6 + 9 + 3 + 5 = 31 → 31 ÷ 3 = 10 remainder 1 Replace blank by 3 - 1 = 2: 826935 is divisible by 3

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the number 3 is divisible by 3

10002

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None. The smallest number divisible by 528 is 528.

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