To test a number to be divisible by 3, add up the digits and if the sum is divisible by 3, so is the original number. If not, the excess over a multiple of 3 gives the remainder when the original number is divided by 3.
Subtract this remainder from 3 and this gives the smallest digit to replace the blank; unless the remainder is 0, in which case the blank can be replaced by a 0:
8 + 6 + 9 + 3 + 5 = 31 → 31 ÷ 3 = 10 remainder 1
Replace blank by 3 - 1 = 2:
826935 is divisible by 3
Let's assume, or hope, that the blank is after those numbers. 67_ and 45_ For a number to be divisible by three, the total of the number's digits has to be divisible by three. 672 and 450
2, 5 or 8.
blank = 2 is a possible answer.
A number is divisible by 3 if the sum of its digits is divisible by 3.
If the number is divisible by 9 the sum of its digits (its digital root) must be divisible by 9. 5+6+8+9 = 28 The next multiple of 9 is 36 and that is 8 more. So the missing digit must be 8.
10,180 is not divisible by six.
A number is divisible by another when the remainder after division by that number is zero.
Its the remainder
10 points are placed in the space