Q: What is the smallest number that leaves a remainder 8 12 when divided by 28 32 respectively?

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64 and 76

119

66 66/16 = 4 and a remainder of 2 66/18 = 3 and a remainder of 12

62 is the smallest number that leaves a remainder of 2 when divided by 3, 4, 5, and 6.

0.25

23

Try 30

85

12*1 + 3 = 15 12*2 + 3 = 27 12*4 + 3 = 51 when 51 divided by 15 gives the remainder as 6.

234568

41

The integer is 157. 157/3 = 52 remainder 1 157/5 = 31 remainder 2 157/7 = 22 remainder 3

2

209

5.2

A number leaves reminder 6 when divided by 10. What is the remainder when the number is divided by 5? Justify your reasoning.

26

121.

Undefined: You cannot divide by zero

No answer is possible as any number divided by 9 must either be exactly divisible by 9 or leave a remainder less than 9.

L.C.M of 17 and 29 is 493.493 + 3 = 496Answer = 496

5

799

71 : Python code that demonstrates this. N = 1 while True : if N % 8 8 : print N break N += 1

11