x-2y=0
x=2y
The solution set is the set of all (x,y) such that x=2y
(2x)ysquared
Whooop!
y = 2x - x2y = 0Since both quantities on the right side are equal to 'y', they're equal to each other.2x - x2 = 0x (2 - x) = 0x = 0and2 - x = 0x = 2The two points of intersection are (0, 0) and (2, 0) .
It is -2y + x2y - 8, which is an expression that cannot be simplified further, not can it be evaluated.
You will get nonsense. You cannot plug x2y + 4 into anything!
4 (apples) plus 3 (apples) = 7 (apples). 4 (cows) + 3 (cows) = 7 (cows) 4 (x2y) + 3 (x2y) = 7 (x2y)
x2y = k (constant) so 36 x 2 ie 72 is the constant. If x = 3 then y = 72/9 = 8
15 percent 0 equals 0; 0 percent 15 equals 0. Both the above are true
xy
The expression "x2y 6" appears to be missing some mathematical operators or context. If you meant to ask about an equation, it could imply "x^2y = 6," suggesting that the product of x squared and y equals 6. To solve for y, you would rearrange it to y = 6/x^2. If you had a different context in mind, please provide more details!
yes
x2 + y - 49 = 0At the x-intercepts, y=0:x2 - 49 = 0(x+7)(x-7) = 0x = -7 and x = +7At the y-intercept, x=0:y - 49 = 0y = 49General Solutionset x=0 to find your y-intercept and set y=0 to find your x-intercept. That's how you will always find your intercepts, no matter what the equation is.Ex. So if you find that when x=0, y=a, then the y-intercept is at the point (0,a).Similarly, if you find that when y=0, x=b, then the x-intercept is at the point (b,0).You can solve any problem from here.