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How do you find the point of intersection between x2 plus y2 equals 5 and x-y equals 1?
x-y = 1 => x = y+1 x2+y2 = 5 => (y+1)(x+1)+y2 = 5 2y2+2y-4 = 0 y = -2 or y = 1 So the points of intersection are: (-1, -2) and (2, 1)
Where are the points of intersection of the equations 4y squared -3x squared equals 1 and x -2y equals 1?
The points of intersection of the equations 4y^2 -3x^2 = 1 and x -2 = 1 are at (0, -1/2) and (-1, -1)
Where are the points of intersection of the parabolas y equals x squared plus 3x -10 and y equals -x squared -8x -15 when plotted on the Cartesian plane?
If: y = x^2 +3x -10 and y = -x^2 -8x -15 Then: x^2 +3x -10 = -x^2 -8x -15 Transposing terms: 2x^2 +11x +5 = 0 Factorizing the above: (2x +1)(x +5) = 0 meaning x = -1/2 or -5 Therefore by substitution points of intersection are at: (-1/2, -45/4) and (-5, 0)
What if zero has an exponent?
it equals 0. 0 x 0 will always be 0
What is the name of the point located at (0 0)?
It is the point of origin which is located at (0, 0) on the Cartesian plane
What is the point of intersection of the lines 6y equals -x -25 and 6x plus 20.5 -y equals 0?
It works out that the point of intersection is at (-4, -3.5) on the Cartesian plane.
What is the point of intersection if y equals x plus 1 and x equals -x plus 1x?
2
What is the point of intersection between the lines y equals 4x -1 and 3y -8x plus 2 equals 0?
The point of intersection of the given simultaneous equations of y = 4x-1 and 3y-8x+2 = 0 is at (0.25, 0) solved by means of elimination and substitution.
What is the point of intersection of the lines 5x plus 7y plus 29 equals 0 and 11x -3y -65 equals 0?
It works out that they intersect at: (4, -7)
What is the point of intersection of the lines 5x plus 7y plus 29 equals 0 and 11x minus 3y minus 65 equals 0?
(4, -7)
Where is the point of intersection of the lines y equals 4x-1 and 3y-8x plus 2 equals 0?
By a process of elimination and substitution the lines intersect at: (1/4, 0)
What is the point of intersection of the parabolas y equals x2 plus 20x plus 100 and y equals x2 -20x plus 100 showing work?
If: y = x2+20x+100 and x2-20x+100 Then: x2+20x+100 = x2-20x+100 So: 40x = 0 => x = 0 When x = 0 then y = 100 Therefore point of intersection: (0, 100)
What is the point of intersection of the lines 5x plus 7y plus 29 equals 0 and 11x -3y -65 equals 0 on the coordinate plane?
By a process of elimination and substitution the lines intersect at: (4, -7)
What is the solution of the system of linear equations x equals 0 and y equals 0?
The solution of the system of linear equations ( x = 0 ) and ( y = 0 ) is the single point (0, 0) in the Cartesian coordinate system. This point represents the intersection of the two equations, where both variables are equal to zero. Thus, the only solution is the origin.
What is the perpendicular distance from the point 4 -2 to the straight line of 2x -y -5 equals 0?
Perpendicular equation: x+2y = 0 Point of intersection: (2, -1) Perpendicular distance: square root of 5
Where are the points of intersection with the x and y axes when y equals 8x2 -26x plus 15 is plotted on the Catesian plane?
Equation: y = 8x^2 -26x+15 Equation when factorized: y = (4x-3)(2x-5) When x = 0 then y = (0, 15) which is the point of intersection on the y axis When y = 0 then x = (3/4, 0) and (5/2, 0) which are the points of intersection on the x axis
What are the coordinates of the intersection point of the x- and y-axis?
They are (0, 0)They are (0, 0)They are (0, 0)They are (0, 0)
